Maximum working shear stress and working force?

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Homework Help Overview

The discussion revolves around calculating the maximum working shear stress and working force for a set of bolts, given parameters such as ultimate shear stress, safety factor, and bolt diameter. The subject area is mechanics of materials, specifically focusing on shear stress and forces in structural components.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore calculations involving shear stress, cross-sectional area, and working force based on provided data. There are attempts to clarify the relationship between ultimate shear stress, safety factor, and maximum working stress. Questions arise regarding unit conversions and the implications of safety factors on working stress.

Discussion Status

Some participants have provided guidance on interpreting the ultimate shear stress and safety factor, suggesting that the maximum working shear stress should be less than the ultimate stress. There is ongoing exploration of the correct calculations and interpretations of the problem, with various interpretations being discussed.

Contextual Notes

Participants note confusion regarding the terminology and units involved, particularly the relationship between ultimate shear stress, safety factor, and working stress. There is also a mention of the need to understand the implications of these factors in the context of the problem.

BlueCB
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Homework Statement



The maximum shear force of a set of bolts is 1000 kN.
The ultimate shear stress is 750 MPa and the safety factor is 3.
The diameter of each bolt is 20 mm.

a) What is the maximum working shear stress in each bolt?

b) The cross sectional area of each bolt?

c) The maximum working force of each bolt?

The Attempt at a Solution



Radius = half of diameter = 10 mm = 1 cm = 0.01 m
Cross sectional area = pi*r^2 = 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2

a) 1000 kN / 0.0314 = 31847133.76 Pa?

b) 3.14*1^2 = 3.14 cm^2 = 0.0314 m^2?

c) Force = Stress*Area = 31847133.76*0.0314 = 1000000 N = 1000 kN?Is the above correct or do completely different formulas apply when it comes to shear stress and working force?
 
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How many square centimeters are in 1 square meter?
 
10,000...
 
BlueCB said:
10,000...

So correct this:
3.14 cm^2 = 0.0314 m^2
 
So 3.14 cm^2 = 0.000314 m^2?

So this would change the other answers:

a) Working shear stress = Force / Area = 1,000,000 N*0.000314 m^2 = 3184713376 Pa?

b) Area = pi*r^2 = pi*1 cm^2 = 3.14 cm^2 = 0.000314 m^2?

c) Working force = Stress*Area = 3184713376 Pa*0.000314 m^2 = 1,000,000 N?
 
Last edited:
Reread the problem statement carefully. Why haven't you used this information:
"The ultimate shear stress is 750 MPa and the safety factor is 3."

Do you understand what this means?
 
SteamKing said:
Reread the problem statement carefully. Why haven't you used this information:
"The ultimate shear stress is 750 MPa and the safety factor is 3."

Do you understand what this means?
If I'm honest, not really:confused:; ultimate shear stress, safety factor, maximum working force? The terminology and what their relative units used are, is really confusing me.

Although would I be right in saying that 750 MPa = 750,000,000 N/m^2?

Some clarification would be very much appreciated.
 
Ultimate stress is the maximum stress which can be sustained before failure. A safety factor is applied to the ultimate stress to produce the maximum allowable safe working stress, item a) above. The safety factor accounts for dynamic loading, stress concentrations, and any other unknown factors in calculating stress. Knowing the maximum safe working stress and the size of the bolts, you should be able to calculate c) above.

In order to work the problem, you must understand the units as well. The pascal is the SI unit of pressure or stress and 1 Pa = 1 N/m^2.
 
Is there a formula for shear stress that involves the ultimate shear stress and safety factor?
 
  • #10
Take this is steps.
1. Knowing the ult. shear stress and the safety factor, what is the max. allowable working stress?
 
  • #11
SteamKing said:
Take this is steps.
1. Knowing the ult. shear stress and the safety factor, what is the max. allowable working stress?
750 MPa = 750,000,000 Pa / 3 = 250,000,000 Pa = 250 MPa (max working stress)?
or
750,000,000 Pa*3 = 2,250,000,000 Pa = 2.25 GPa (max working stress)?
 
  • #12
BlueCB said:
750 MPa = 750,000,000 Pa / 3 = 250,000,000 Pa = 250 MPa (max working stress)?
or
750,000,000 Pa*3 = 2,250,000,000 Pa = 2.25 GPa (max working stress)?
It's a safety factor. To be safe, do you think the working stress to which it should be subjected would be more or less than its calculated ultimate stress?
 
  • #13
haruspex said:
It's a safety factor. To be safe, do you think the working stress to which it should be subjected would be more or less than its calculated ultimate stress?
Less, would make more sense (if its to be safe).

So in that case, does 250 MPa sound about right for the max working shear stress?

And then: max working shear stress*cross sectional area = max working force
= 250,000,000 Pa*0.000314 m^2 = 78500 N = 78.5 kN?
 
Last edited:
  • #14
BlueCB said:
Less, would make more sense (if its to be safe).

So in that case, does 250 MPa sound about right for the max working shear stress?

And then: max working shear stress*cross sectional area = max working force
= 250,000,000 Pa*0.000314 m^2 = 78500 N = 78.5 kN?

Looks right.
 
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