Number of Possible 3-Card Hands with and without Order Consideration

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Homework Help Overview

The discussion revolves around calculating the number of possible 3-card hands from a set of 9 cards numbered 1 to 9, considering both scenarios where order matters and where it does not.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definitions of combinations and permutations, questioning the original poster's use of these concepts. There are attempts to clarify the correct application of these terms in the context of the problem.

Discussion Status

There is ongoing confusion regarding the correct calculations and terminology. Some participants are questioning the validity of previous answers and seeking clarification on the concepts involved. Multiple interpretations of the problem are being explored, but no consensus has been reached.

Contextual Notes

Participants are addressing potential misunderstandings about the definitions of combinations and permutations, indicating a need for clearer definitions in the context of the problem.

r-soy
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Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?


----------Ansewr >>


1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536
 
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Could you please elaborate on your thinking behind your answers?

You have C and P backwards. Combinations is when you don't care about the order; permutations is when you do. "123" and "321" are the same combination, but they are two possible permutations of 1, 2, and 3.


r-soy said:
Q : Suppose 9 cards are number with the 9 digits from 1 to 9 . A 3-card hand is dealt, 1 card at a time . How many hands are possible where :

1 ) Order is taken into consideration ?

2 ) order is not taken into considreation ?


----------Ansewr >>


1 - 9C3 X 9C1 = 84 X 9 = 756

2 - 9P3 X 9P1 = 504 X 9 = 4536
 
Is my answer correct ?
 
r-soy said:
Is my answer correct ?

read vela's post.
 
The ansewr now correct ?

1 - 9P3 X 9P1 = 504 X 9 = 4536

2 - 9C3 X 9C1 = 84 X 9 = 756
 
No, they are not.
 
Help me Give me the answer
 
No .
 
I tay agine

1 - 9C2 X 9C1 = 36 X 9 = 324

2 - 9P2 X 9P1 = 72 X 9 = 648
 
  • #10
Please elaborate on your thinking behind your answers?
 
  • #11
I can't try more thanks all
 

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