Number Theory. Argue Is not the square of an integer.

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The discussion focuses on demonstrating that the expression (17^4)*(5^10)*(3^5) is not the square of an integer. The key argument is based on the prime factorization and the exponents of each prime factor. While 17^4 and 5^10 are perfect squares, 3^5 is not, as its exponent (5) is odd. This indicates that the overall product cannot be a perfect square since all prime factors must have even exponents for the product to be a square. Thus, the conclusion is that (17^4)*(5^10)*(3^5) is not the square of an integer.
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Homework Statement


Argue that (17^4)*(5^10)*(3^5) is not the square of an integer.



Homework Equations


N/A?


The Attempt at a Solution


Do I break these up, and show that each is not a square? I'm not sure if that would be correct, but sqrt(17^4)=289 * sqrt(5^10)=3125 * sqrt(243)=15.5884 =...

Since sqrt(243)=15.5884 and is not an integer then the above is not the square of an integer. Is this an efficient explanation?
 
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Well, it certainly doesn't show any understanding of the problem! Look at the exponents: \sqrt{17^4}= (17^4)^{1/2}= 17^2. \sqrt{5^{10}}= (5^{10})^{1/2}= 5^5. What about \sqrt{3^5}?

Do you see why the fact that 3, 5, and 17 are prime numbers is important?
(Consider the same question about \sqrt{(8)(18)}.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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