Number Theory divisibility proof

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Homework Help Overview

The problem involves proving that the expression (n(n+1)(n+2) + 21) is divisible by 3 for any positive integer n. It falls within the subject area of number theory, specifically focusing on divisibility properties.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to leverage a previously proven lemma about divisibility. They express a need for guidance on proving that n(n+1)(n+2) is divisible by 3, noting that they have tried expanding the expression without success.

Discussion Status

Some participants acknowledge the original poster's insight regarding the product of consecutive integers, suggesting a potential realization about the divisibility of n(n+1)(n+2) by 3. However, there is no explicit consensus or resolution reached in the discussion.

Contextual Notes

The discussion references a lemma related to divisibility, and the original poster is working within the constraints of a homework assignment that requires a proof rather than a direct solution.

jersiq1
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Homework Statement


Prove that for any n [tex]\in[/tex] Z+, the integer (n(n+1)(n+2) + 21) is divisible by 3


Homework Equations



A previously proved lemma (see below)

The Attempt at a Solution



I sort of just need a nudge here. I have a previously proven lemma which states:

If d|a and d|b, then d|(a+b)

So armed with this I see that obviously 3|21 and all that remains is to prove n(n+1)(n+2) is divisible by 3. I have tried expanding, which didn't seem to help.
 
Physics news on Phys.org
n(n+1)(n+2) is the product of __ consecutive integers.
 
Wow! staring me in the face. Thanks.
 
Cheers :)
 

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