Number theory: finding integer solution to an equation

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Homework Help Overview

The discussion revolves around finding integer solutions to the equation \(x^2 + y^2 = 6 + 2xy + 3x\), which falls under the subject area of number theory. Participants are exploring various algebraic manipulations and substitutions to analyze the equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants attempt to rearrange the equation and express it in different forms, such as \( (x-y)^2 = 3(x+2) \). There are discussions about the implications of certain substitutions and the properties of the variables involved, particularly concerning modular arithmetic.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning each other's reasoning. Some have suggested potential substitutions and explored the implications of their definitions, while others are seeking clarification on the relationships between the variables.

Contextual Notes

There are indications of confusion regarding the divisibility of certain expressions and the implications of modular conditions. Participants are also grappling with the challenge of deriving integer solutions from the established relationships.

mtayab1994
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Homework Statement



(E): x^2+y^2=6+2xy+3x

The Attempt at a Solution



[tex]x^{2}+y^{2}=6+2xy+3x\Longleftrightarrow x^{2}-2xy-3x+y^{2}=6\Longleftrightarrow x^{2}+x(-2y-3)+y^{2}=6[/tex]

Any further help to find the answer??
 
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You might try looking at ##x^2 - 2xy+y^2=6+3x##
 
Joffan said:
You might try looking at ##x^2 - 2xy+y^2=6+3x##

That's [tex](x-y)^{2}-3x=6[/tex]
 
mtayab1994 said:
That's [tex](x-y)^{2}-3x=6[/tex]
Or ##(x-y)^2=3(x+2)## - which should be more interesting.
 
Joffan said:
Or ##(x-y)^2=3(x+2)## - which should be more interesting.

Can we use substitution and say that x+2=n?
 
mtayab1994 said:
Can we use substitution and say that x+2=n?
Sure, although we will find a better substitution... what can you tell me about ##n##?
 
Joffan said:
Sure, although we will find a better substitution... what can you tell me about ##n##?

On the question before I proved that x^2 Ξ 0(mod3) and that means that x^2=3n.
 
mtayab1994 said:
On the question before I proved that x^2 Ξ 0(mod3) and that means that x^2=3n.
Hmm, not really. Let's define ##m:=(x-y)## - what can you tell me about ##m##?
 
Joffan said:
Hmm, not really. Let's define ##m:=(x-y)## - what can you tell me about ##m##?

That means that m is the difference of x and y.
 
  • #10
mtayab1994 said:
That means that m is the difference of x and y.

My question is, what does ##m^2=3n## (using the new definitions) tell you about ##m##?
 
  • #11
Joffan said:
My question is, what does ##m^2=3n## (using the new definitions) tell you about ##m##?

That means that m^2 is divisible by 3 hence divisible by all multiples of 3.
 
  • #12
Is that what you meant to say? 81 is divisible by 3, but it's not divisible by 6, which is a multiple of 3.
 
  • #13
mtayab1994 said:
That means that m^2 is divisible by 3
Yes... what does that mean for ##m##?
mtayab1994 said:
... hence divisible by all multiples of 3.
What? No. For example, 36 is divisible by 3 but not by 15.
 
  • #14
vela said:
Is that what you meant to say? 81 is divisible by 3, but it's not divisible by 6, which is a multiple of 3.

If we said that m=x-y then m^2=(x-y)^2=3n .
So then we get that (x-y)^2=3n right?
 
  • #15
Yes, but it doesn't follow that m2 is divisible by all multiples of 3, which is what you claimed.
 
  • #16
vela said:
Yes, but it doesn't follow that m2 is divisible by all multiples of 3, which is what you claimed.


But how are we supposed to find integer solutions out of that? I found that y=n^2-3n-2 and that's wrong I think.
 
  • #17
At this point, you're going to have to think about it a bit on your own. You've got all the pieces. You just need that last little insight, which is what Joffan's been trying to get you to see.
 
  • #18
Joffan said:
My question is, what does ##m^2=3n## (using the new definitions) tell you about ##m##?

Which new definitions m=x-y?
 
  • #19
mtayab1994 said:
Which new definitions m=x-y?
Don't backtrack. We have defined new variables ##m## and ##n##; the formula translates into those variables as shown; now you need to understand what ##m^2=3n## tells you about ##m##.
 
  • #20
Joffan said:
Don't backtrack. We have defined new variables ##m## and ##n##; the formula translates into those variables as shown; now you need to understand what ##m^2=3n## tells you about ##m##.

Well there are 3 cases:

Case 1: if m Ξ 0(mod3) then m^2 Ξ 0(mod3)

Case 2: if m Ξ 1(mod3) then m^2 Ξ 1(mod3)

Case 3: if m Ξ 2(mod3) then m^2 Ξ 4(mod3) with is m^2 Ξ 1(mod3)

So that means that m^2=3n . So that means the when m is divided by 3 you get either a remainder of 0,1, or 2 am i right?
 
  • #21
mtayab1994 said:
Well there are 3 cases:

Case 1: if m Ξ 0(mod3) then m^2 Ξ 0(mod3)

Case 2: if m Ξ 1(mod3) then m^2 Ξ 1(mod3)

Case 3: if m Ξ 2(mod3) then m^2 Ξ 4(mod3) with is m^2 Ξ 1(mod3)
Looks good.

So that means that m^2=3n . So that means the when m is divided by 3 you get either a remainder of 0,1, or 2 am i right?
How did you come up with that conclusion based on what you wrote above?
 
  • #22
What is the value of ##3n## mod 3?
 
Last edited:
  • #23
Joffan said:
What is the value of ##3n## mod 3?

3n mod 3 means that 3n=3k so that means 3k equals the multiples of 3 which are 3n.
 

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