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trap101
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I have two full questions on some number theory questions I've been working on, I guess my best bet would be to post them separately.
1) Suppose that n is in N (natural numbers), p1,...,pn are distinct primes, and l1,...ln are nonnegative integers. Let m = p1l1p2l2...pnln. Let d be in N such that d ≥ 2 and d divides m.
a) Using the fundamental theorem of arithemetic prove that p is a prime that divides d, then pi for some i in {1,...,n}.
Attempt: Since d is in N and d ≥ 2, this means that d itself is a product of primes (prime factorization) or a prime itself. This means d = p1p2...pn (product of primes). Then there exists a p that divides d. (Since we are starting from 1 in the natural numbers)
Is this the right idea and what would be a clearer way of writing this as a proof?
b) Suppose the i is in {1,...,n}. Prove that pik does not divide d if
k > li
Attempt: if k > li then d ≠ pik, but d may equal any prime in m = p1l1p2l2...pnln since we know d | m.
this would imply d has a cononical factorization : p1l1p2l2...pnln and we know k > li therefore pik does not divide d.
Right idea?
1) Suppose that n is in N (natural numbers), p1,...,pn are distinct primes, and l1,...ln are nonnegative integers. Let m = p1l1p2l2...pnln. Let d be in N such that d ≥ 2 and d divides m.
a) Using the fundamental theorem of arithemetic prove that p is a prime that divides d, then pi for some i in {1,...,n}.
Attempt: Since d is in N and d ≥ 2, this means that d itself is a product of primes (prime factorization) or a prime itself. This means d = p1p2...pn (product of primes). Then there exists a p that divides d. (Since we are starting from 1 in the natural numbers)
Is this the right idea and what would be a clearer way of writing this as a proof?
b) Suppose the i is in {1,...,n}. Prove that pik does not divide d if
k > li
Attempt: if k > li then d ≠ pik, but d may equal any prime in m = p1l1p2l2...pnln since we know d | m.
this would imply d has a cononical factorization : p1l1p2l2...pnln and we know k > li therefore pik does not divide d.
Right idea?
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