Number Theory - Primitive Roots

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A primitive root modulo 19 is determined to be 2, as it has an order of 18. To find all primitive roots modulo 19, one must identify values of g that satisfy g^18 ≡ 1 mod 19, while avoiding those that also satisfy g^9 ≡ 1 or g^6 ≡ 1. The discussion emphasizes that the unit group of Z/19Z forms a cyclic group of order 18, which is crucial for understanding primitive roots. The conversation reveals a learning moment about the underlying algebraic concepts, clarifying the importance of excluding certain conditions. Overall, the process of finding primitive roots involves recognizing the structure of the group and the significance of the order of elements.
mattmns
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Here is the question from the book:
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Determine a primitive root modulo 19, and use it to find all the primitive roots.
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\varphi(19)= 18

And 18 is the order of 2 modulo 19, so 2 is a primitive root modulo 19, but I am not sure of how to use that to find all primitive roots modulo 19. My only idea is that we need to find what values of g satisfy g^{18} \equiv 1 \ \text{mod 19}. However, I am not sure how to solve that equation. Any ideas? Thanks!
 
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Well, you know that the unit group of Z/19Z is simply a cyclic group of order 18, right?

If that doesn't help, don't forget that g is a power of 2. Now, you know that everything in Z/19Z satisfies g^18 = 1... the things you're interested in are the things that do not also satisfy g^9 = 1 or g^6 = 1. (Do you see why?)
 
Unfortunately I don't know much algebra, and our number theory class has not focused on the algebra behind it, so I don't really understand what you are saying.
 
Z/19Z is simply the residue classes modulo 19.
 
Thanks, now I see the idea behind it, and I see how to find the others. Seems kind of obvious now :redface:
 
why are we interested in the things that DO not satisfy g^9 = 1 or g^6 = 1?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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