# Numbers in Ascending Order in C++

• C/++/#
i have to write such a program that takes 10 integers from user and show them in ascending order.

My attempt was ---

#include<iostream.h>
#include<conio.h>

int main()
{
int a[10];

for(int i=0; i<10; i++) //this loop is used for getting the 10 integers from user
cin>>a;

...................... // here I'm stuck. I couldn't find how should i sort them. I can sort
// number using 'if..else if' statement which makes the program lengthy
// for this propblem.

getch();
return 0;
}

So plz help me if any one knows how to sort 10 integers so that it doesn't make the codes lengthy.

Why not just use qsort? Or are you required to actually write the low-level sorting algorithm directly? If so, I'd look at the Wikipedia pages on qsort and heapsort for some ideas; they have pretty good explanations and psuedocode.

Integral
Staff Emeritus
Gold Member
A bubble sort is quick and easy to code. Simple go through your list swaping adjacent numbers if they are out of order. Repeat until there are no swaps.

jim mcnamara
Mentor
If you are allowed to use the stl and the vector container, try sort().

thanks to all replied...Actually I'm newbie in c++. I haven't studied qsort, heapsort or vector container..
swapping technique is suitable for my level...I used it in the for loop

for(int p=0; p<9; p++)
{
for(int i=0; i<9; i++)
{
if(a>a[i+1]) // comparison between two adjacent array elements
{
holder=a; // holder holds the value temporarily
a=a[i+1];
a[i+1]=holder;
}
}
}

mgb_phys
Homework Helper
Depends what sort of class this is !
If you are supposed to write the sort then bubble sort is easiest - justify your choice over a qsort by saying that the speed difference is small for only 10numbers !
If this is a real programming class then use.

vector<int>a;
for( ....
a.push_back( input )
}

sort(a.begin(),a.end());

obviously it vl not show the output coz nobody written cout<<a;
line anywhere
i tried to write it at d end of all for loops bt it shows address of a integer

rcgldr
Homework Helper
cout<<a;
You'd need a loop and use cout<<a; .

mdnazmulh, do not use the header iostream.h. It is deprecated, and not part of standard C++.

Code:
#include <iostream>

And unless you want to prefix standard library names with "std::" use the following.

Code:
using namespace std;

If you are allowed to use the stl and the vector container, try sort().

std::sort would work with arrays/pointers too.

Code:
#include <iostream.h>
void main()
{
const int max=50; //sets the maximum size of the array
int num[max]; //the array can be initialized from here num={2,3,6,4,3,7,8,,4.....n};
int holder;
//if array is initialized then no need for this for loop
for(int m=0; m<max; m++)
{
cout<<"Enter number "<<(m+1)<<" : ";
cin>>num[m];
}

for(int p=0; p<(max-1); p++)
{
for(int i=0; i<(max-1); i++)
{
if(num[i]>num[i+1]) // comparison between two adjacent array elements
{
holder=num[i]; // holder holds the value temporarily
num[i]=num[i+1];
num[i+1]=holder;
}
}
}
//now to print the sorted array
for(int j=0; j<max; j++)
{
cout<<" "<<num[j];        //This prints the array out in ascending order on the same line
//<<endl; could be placed at the end to print on different line
}
}

Last edited by a moderator:
#include <iostream.h>
#include<conio.h>

void main ( )
{
int arr[100] , size , hold ;
START :
cout << "\n Enter the size of the array ( not more than 100 ) : " ;
cin >> size ;
if ( size > 100 )
{
cout << "\n Size is more than 100 ... Please re enter .. " ;
getch ( ) ;
clrscr ( ) ;
goto START ;
}
cout << "\n Enter " << size << "elements ... \n" ;
for ( int i = 0 ; i < size ; i ++ )
cin >> arr;
for ( i = 0 ; i < (size-1) ; i++ )
{
for ( int j = i+1 ; j < size ; j++ )
{
if ( arr[j] < arr )
{
hold = arr[j] ;
arr[j] = arr ;
arr = hold;
}
}
}
cout << "\n The sorted array : \n ";
for ( i=0 ; i < size ; i++ )
cout << arr[size] << " ";
getch ( ) ;
}