Numerical Analysis: Interpolatory Requirement & Coefficient Conditions

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SUMMARY

The discussion focuses on the rational function R(x) = (a + bx) / (c + dx) and its interpolatory requirement R(xi) = yi for i = 1, 2, 3, 4. The key conclusion is that a unique solution for the coefficients a, b, c, and d exists when the associated 4x4 matrix A is invertible, which requires additional equations beyond the four provided by the interpolation conditions. The participant identifies the need for 12 more equations to achieve a unique solution, highlighting the complexity of the problem.

PREREQUISITES
  • Understanding of rational functions and their properties
  • Familiarity with linear algebra concepts, particularly matrix invertibility
  • Knowledge of interpolation methods in numerical analysis
  • Experience with solving systems of equations
NEXT STEPS
  • Study the conditions for matrix invertibility in linear algebra
  • Explore interpolation techniques, specifically polynomial interpolation
  • Learn about the role of additional constraints in solving systems of equations
  • Investigate the application of rational functions in numerical analysis
USEFUL FOR

This discussion is beneficial for students and professionals in numerical analysis, particularly those working with interpolation methods and rational functions. It is also useful for anyone studying linear algebra and seeking to understand the conditions for unique solutions in systems of equations.

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Homework Statement


take the rational function R(x)=(a+bx)\(c+dx). What does the interpolatory requirment R(xi)=yi, i=1,2,3,4 amount to? under what conditions can you find coefficients? uniquely?


Homework Equations





The Attempt at a Solution


Let y=[y1,y2,y3,y4] and v=[a,b,c,d] and let A be an 4x4 matrix. then I want to try to write this as Av=y and the solution would would exist and be unique when A is invertible. so I write a+bxi=(c+dxi)yi. then I can write a+bxi-cyi-d(xi)(yi)=0 but this won't give me the solution because we could just write a=b=c=d=0 for any x and y. since I know yi and xi I could have a+bxi-cyi = d(xi)(yi) and set up the matrix that way but it still won't give me what I want since I wouldn't be able to find d. Am I on the right track? any suggestions on where to go from here? thanks
 
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In A you have 16 matrix elements, but Av = y corresponds to only 4 equations. You need 12 more equations for a unique solution.
 

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