Nyquist Plot Intersection with Real Axes

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To determine the intersection of a Nyquist plot with the real axis, substitute 'jω' into the transfer function and set the real part equal to zero, solving for ω. A quicker method involves testing values of ω to find where the imaginary part changes sign, indicating an intersection. For complex equations involving arctan, numerical methods like Newton's method can be useful for finding solutions. An example transfer function, F(s) = 10*(s+5)/(s-1)^3, can be analyzed similarly by applying these techniques. Understanding these methods is crucial for effectively applying the Nyquist stability criterion in tests.
nebbione
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Hi everyone, I'm real confused and stucked about a point in applying Nyquist stability criterion... now i'll explain why.

I know that it's needed to know how many times I'm wrapping the nyquist critical point (-1;0) with my plot, and I'm enough good to draw by hand a nyquist plot, but the problem is to determine analitically the intersection value of the plot in which I'm interssecting the real axes, I've heard that i have to substitute 'jω' in my transfer function and after i have to divide the real part from the imaginary part of my transfer function and then find out the ω where I'm intersecting the real axes putting the real part of the transfer function equal to zero. Mathematically speaking : RealPart(F(jω))=0 where F is my transfer function.
Once I've found the ω i substitute that ω in my transfer function to find the exact point where I'm intersecting the real axes.
My first question is : Is there a quicker way to compute this point without using software, since I need it for a test ?

I've heard about the arctan way of computing the phase, but the problem is that if I put an equation (for example) like this :
arctan(w/3)+arctan(w/5)-3arctan(w/10)=-180

it's impossible for me to solve it...i don't know how to handle these arctan equations, my second question is : Is there a way to compute it ? And if not, which is the way to solve this problem ?
 
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nebbione said:
My first question is : Is there a quicker way to compute this point without using software, since I need it for a test ?
You could use Im(F(jω)) (edit: You meant Im(F(jω)) = 0 ?) and just punch in likely values for ω (on a calculator) until you find the sign change. That should put you close enough to the intersection with the real axis for a quick sketch.

nebbione said:
... my second question is : Is there a way to compute it ?
By hand? It's easy for some systems, hard for others. I had a very basic implementation of Newton's method on my calculator to solve equations like that numerically. Came in handy now and then.
 
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Can you make me an example ?
For example if i have a transfer function like : F(s)= 10*(s+5)/(s-1)^3 how should i proceed ?
 
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