Obtaining Higher Angular Frequencies in QHO Excited States

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Discussion Overview

The discussion revolves around the behavior of the quantum harmonic oscillator (QHO) and the nature of its excited states, specifically focusing on the angular frequencies associated with these states. Participants explore the relationship between energy levels and angular frequencies in the context of quantum mechanics.

Discussion Character

  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions why excited states of the quantum harmonic oscillator vibrate with higher angular frequencies despite having a natural frequency \(\omega_0\).
  • Another participant suggests that increasing the energy of a harmonic oscillator necessitates an increase in frequency, although the reasoning behind this is not fully elaborated.
  • A later reply indicates that the time-dependent part of the wave function for excited states can be expressed as \(e^{-i(n+1/2)\omega t}\), implying that as the quantum number \(n\) increases, the frequency also increases.
  • Another participant confirms the correctness of the previous statement regarding the time-dependent part, relating it to the Hamiltonian of the system.

Areas of Agreement / Disagreement

Participants generally agree on the relationship between the quantum number \(n\) and the angular frequency of the excited states, but the initial question regarding the nature of these frequencies remains somewhat open to interpretation.

Contextual Notes

The discussion does not address potential limitations or assumptions regarding the definitions of frequency and energy in the context of the quantum harmonic oscillator.

copernicus1
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Maybe the answer to this should be obvious, but if the quantum harmonic oscillator has a natural angular frequency \omega_0, why do the excited states vibrate with higher and higher angular frequencies? How do we obtain these frequencies?

Thanks!
 
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Maybe I didn't understand your question but this is quite the definition of "higher state". In order to increase an harmonic oscillator energy its frequency must grow.
 
Thanks, I think I understand it now. Normally the time-dependent part would look like $$e^{-i\omega t},$$ but I suppose in this case it essentially looks like $$e^{-i(n+1/2)\omega t}.$$ So as the n value increases the frequency will increase. Does this look correct?

Thanks.
 
That's correct. The time-dependent part, in fact, generally is exp(-iHt) so, in your case H=(n+1/2)\hbar\omega and you get exactly what you wrote.
 

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