The discussion revolves around solving a quadratic equation in Octave, obtaining its roots, and subsequently using these roots to solve a system of equations. Participants explore the process of extracting roots and applying them in further calculations, specifically in the context of a mathematical problem involving equations.
The discussion does not appear to reach a consensus on the best approach initially, as participants express different levels of understanding and methods for accessing the roots. However, the original poster ultimately finds a solution to their problem.
Participants discuss the specifics of using Octave for calculations, including the structure of matrices and functions, but do not provide detailed mathematical derivations or assumptions underlying their approaches.
Individuals working on quadratic equations in Octave, particularly those seeking to understand how to manipulate and use roots in further mathematical tasks.
It seems like you've already done the hard work. The equation ##x + y = c## is equivalent to ##y = -x + c##. Can't you just substitute x1 and x2 here and find y?Ugnius said:Homework Statement:: .
Relevant Equations:: .
Hi , I had to solve a quadratic equation , i got two roots as an answer ( ans= x1 / x2) , and now i need to use one of those answers to complete further tasks like finding y from x+y=c so i need to use x1 and x2 from roots , i was wondering if that's possible and how
yea that what i am not able to do because i don't know what function i need to call to get the root1 and root2 as variablesMark44 said:It seems like you've already done the hard work. The equation ##x + y = c## is equivalent to ##y = -x + c##. Can't you just substitute x1 and x2 here and find y?
I have solved it 3 AM last night , the point was that roots was a 1x2 matrix , but i could use because it was plugged in octave variable so i created another 1x2 matrix , made it equal to roots(A) matrix , and then i could use B(1) and B(2) to get 1st and 2nd root as variables , thanks for the help tho !Mark44 said:Have you written a function that calculates the roots of a quadratic? Your function, if you have one, should return two values. Show us the Octave code you have.