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Odd Challenge Question in Algebra I Book

  1. Sep 25, 2012 #1
    1. The problem statement, all variables and given/known data
    An even integer can be written as the expression 2n. Find three consecutive even integers with a sum of 54.


    2. Relevant equations
    None, this was a challenge question.


    3. The attempt at a solution
    I got that the sum of the digits in 104 (2*52) equals 54 but cannot see any other solutions.
     
  2. jcsd
  3. Sep 25, 2012 #2
    Please close thread
     
  4. Sep 25, 2012 #3
    The problem is this.

    Find three integers (even) a, b and c such that

    a + b + c = 54

    where a = b-2 and c= b+2
    So:

    (b-2) + b + (b+2) = 54

    From there you can solve for b, and then find a and c.
     
  5. Sep 25, 2012 #4

    Mark44

    Staff: Mentor

    The sum of the digits in 104 is 1 + 0 + 4 = 5.
     
  6. Sep 25, 2012 #5
    I know what I did wrong now
    Thank you all
    I now ask that this thread be locked or deleted
     
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