Odd Challenge Question in Algebra I Book

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Homework Help Overview

The problem involves finding three consecutive even integers that sum to 54, expressed in terms of a variable representing even integers.

Discussion Character

  • Exploratory, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the formulation of the problem, with one suggesting a method to express the integers in terms of a variable and setting up an equation to solve for it.

Discussion Status

The discussion includes attempts to clarify the problem setup and explore potential solutions. One participant expresses confusion regarding their previous reasoning but acknowledges a mistake, leading to a request to close the thread.

Contextual Notes

Participants note that this is a challenge question without specific equations provided, which may contribute to the exploratory nature of the discussion.

dbmorpher
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Homework Statement


An even integer can be written as the expression 2n. Find three consecutive even integers with a sum of 54.


Homework Equations


None, this was a challenge question.


The Attempt at a Solution


I got that the sum of the digits in 104 (2*52) equals 54 but cannot see any other solutions.
 
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Please close thread
 
The problem is this.

Find three integers (even) a, b and c such that

a + b + c = 54

where a = b-2 and c= b+2
So:

(b-2) + b + (b+2) = 54

From there you can solve for b, and then find a and c.
 
dbmorpher said:

Homework Statement


An even integer can be written as the expression 2n. Find three consecutive even integers with a sum of 54.

Homework Equations


None, this was a challenge question.

The Attempt at a Solution


I got that the sum of the digits in 104 (2*52) equals 54 but cannot see any other solutions.
The sum of the digits in 104 is 1 + 0 + 4 = 5.
 
Mark44 said:
The sum of the digits in 104 is 1 + 0 + 4 = 5.

I know what I did wrong now
Thank you all
I now ask that this thread be locked or deleted
 

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