Odd Challenge Question in Algebra I Book

AI Thread Summary
The challenge question involves finding three consecutive even integers that sum to 54. The integers can be expressed as a, b, and c, where a = b-2 and c = b+2. The equation simplifies to (b-2) + b + (b+2) = 54, allowing for the calculation of b. The user initially miscalculated the sum of the digits in 104 but later recognized the error and requested the thread to be closed. The solution process is clarified, leading to a better understanding of the problem.
dbmorpher
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Homework Statement


An even integer can be written as the expression 2n. Find three consecutive even integers with a sum of 54.


Homework Equations


None, this was a challenge question.


The Attempt at a Solution


I got that the sum of the digits in 104 (2*52) equals 54 but cannot see any other solutions.
 
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The problem is this.

Find three integers (even) a, b and c such that

a + b + c = 54

where a = b-2 and c= b+2
So:

(b-2) + b + (b+2) = 54

From there you can solve for b, and then find a and c.
 
dbmorpher said:

Homework Statement


An even integer can be written as the expression 2n. Find three consecutive even integers with a sum of 54.

Homework Equations


None, this was a challenge question.

The Attempt at a Solution


I got that the sum of the digits in 104 (2*52) equals 54 but cannot see any other solutions.
The sum of the digits in 104 is 1 + 0 + 4 = 5.
 
Mark44 said:
The sum of the digits in 104 is 1 + 0 + 4 = 5.

I know what I did wrong now
Thank you all
I now ask that this thread be locked or deleted
 

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