ODE homogeneous equations w/constant coefficients

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Homework Help Overview

The discussion revolves around finding the general solution to the homogeneous ordinary differential equation (ODE) with constant coefficients, specifically the equation y'' + 3y' + 2y = 0. Participants are exploring the implications of the order of terms in the general solution.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the roots of the characteristic equation derived from the ODE and the resulting general solution. There is a question regarding whether the order of the terms in the solution matters, with some expressing uncertainty about the conventions used in presenting solutions.

Discussion Status

Some participants have provided insights into the conventions regarding the order of terms in the general solution, suggesting that while there are no strict rules, certain preferences exist. The conversation is ongoing, with participants seeking clarification on notation and the implications of order in the solution.

Contextual Notes

There is mention of confusion regarding the notation used for the exponential terms in the general solution, indicating a need for clarity in mathematical expressions. Participants are also considering how to present their solutions in accordance with common conventions.

mmont012
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Homework Statement


Find the general solution
y"+3y'+2y=0

Homework Equations


y(t) =c_1e^r_1t + c_2e^r_2t

The Attempt at a Solution


a=1 b=3 c=2
r^2+3r+2=0
(r+2)(r+1)=0
r_1=-2
r_2=-1

General solution: y(t) =c_1e^(-2t)+c_2e^(-t)I was wondering if the order mattered. The answer in the book is y(t)=c_1e^(-t)+c_2e^(-2t)

I don't think that it does, but I want to make sure before continuing and submitting my hw.
If the order DOES matter, how can I get the correct order?

Thank you.
 
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mmont012 said:

Homework Statement


Find the general solution
y"+3y'+2y=0

Homework Equations


y(t) =c_1e^r_1t + c_2e^r_2t

The Attempt at a Solution


a=1 b=3 c=2
r^2+3r+2=0
(r+2)(r+1)=0
r_1=-2
r_2=-1

General solution: y(t) =c_1e^(-2t)+c_2e^(-t)I was wondering if the order mattered. The answer in the book is y(t)=c_1e^(-t)+c_2e^(-2t)
No, the order doesn't matter
mmont012 said:
I don't think that it does, but I want to make sure before continuing and submitting my hw.
If the order DOES matter, how can I get the correct order?
By the way, what you wrote as a relevant equation confused me for a while.
c_1e^r_1t + c_2e^r_2t
For the two functions, are they ##e^{r_1}t## and ##e^{r_2}t## or are they ##e^{r_1t}## and ##e^{r_2t}##?
I know what you mean, but if you write them inline as you did, at the least use parentheses around the exponent, such as e^(r_1t).
 
Thank you, and sorry about the confusion. I'm using my phone and its acting up. Next time I'll be sure to add ().
 
mmont012 said:

Homework Statement


Find the general solution
y"+3y'+2y=0

Homework Equations


y(t) =c_1e^r_1t + c_2e^r_2t

The Attempt at a Solution


a=1 b=3 c=2
r^2+3r+2=0
(r+2)(r+1)=0
r_1=-2
r_2=-1

General solution: y(t) =c_1e^(-2t)+c_2e^(-t)I was wondering if the order mattered. The answer in the book is y(t)=c_1e^(-t)+c_2e^(-2t)

I don't think that it does, but I want to make sure before continuing and submitting my hw.
If the order DOES matter, how can I get the correct order?

Thank you.

Either order is correct because there are not really any rules about that.

However, sometimes authors adopt certain conventions, such as having the most slowly-decreasing functions first, followed by more rapidly-decreasing functions. In that convention, ##e^{-t}## decreases more slowly than ##e^{-2t}##, so would come first. In the opposite case of increasing functions, people sometimes want the most rapidly-increasing functions to come first, in part because they govern the asymptotic large-##t## behavior. So, if you had increasing functions ##e^{t}## and ##e^{2t}##, some people might write the ##e^{2t}## first.

However, as I said, there really are no rules, and not everyone subscribes to the type of conventions I have mentioned.
 

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