ODE problem -- Find the amount salt in the tank as water flows through it

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SUMMARY

The discussion focuses on solving an ordinary differential equation (ODE) related to a tank containing saltwater. Initially, the tank has 100 gallons of fresh water, and saltwater with a concentration of 1/2 lb per gallon is introduced at a rate of 2 gallons per minute for 10 minutes. After this period, fresh water replaces the saltwater at the same rate. The participants clarify the correct application of the integrating factor, specifically e^(0.02t), and emphasize that the solution should not include S1(t) within the integral. The correct formulation is essential for accurately determining the amount of salt in the tank after the entire process.

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yecko
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Homework Statement



A tank originally contains 100 gal of fresh water. Then water containing 1/2 lb of salt per gallon is poured into the tank at a rate of 2 gal/min, and the mixture is allowed to leave at the same rate. After 10 min the process is stopped, and fresh water is poured into the tank at a rate of 2 gal/min, with the mixture again leaving at the same rate. Find the amount salt in the tank at the end of an additional 10 min.
2018-02-15-9-59-55-png.png

How can the two highlighted part obtain?

Homework Equations


y(t)=(1/μ(t)) ∫ {from to to t} [yoμo+∫(g(t)μ(t))dt]

The Attempt at a Solution


I have tried to substitute the formula, S1(t)=e^(-0.02t) * ∫ {from 0 to t} (S1(t)/50)e^(0.02t) dt
which seems wrong...

Thanks
 

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Did you try inserting the expression for the integrating factor and checking the equation explicitly? You should find that this gives you back the ODEs for ##S_1## and ##S_2##, respectively.
 
yecko said:
S1(t)=e^(-0.02t) * ∫ {from 0 to t} (S1(t)/50)e^(0.02t) dt
integrating factor: e^(0.02t)
but S1(t) and t both have to integrate while I do not actually know what is S1(t), how can I integrate it?
thanks
 
Your formula is not correct. It should not contain ##S_1(t)## in the integral. See the general form of the solution in the other thread.
 

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