# of electron states in a subshell

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SUMMARY

The number of electron states in a subshell with an orbital quantum number l = 3 is definitively 14. This is derived from the fact that for l = 3, the magnetic quantum number m can take on 7 values ranging from -3 to +3. Each of these values corresponds to two possible spin states, resulting in a total of 14 electron states. The calculations confirm that the correct answer to the homework question is option C.

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  • Understanding of quantum numbers: principal (n), azimuthal (l), and magnetic (m).
  • Familiarity with electron configurations and subshells in atomic structure.
  • Knowledge of spin quantum numbers and their implications for electron states.
  • Basic principles of quantum mechanics as they relate to atomic orbitals.
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  • Review the differences between s, p, d, and f orbitals in terms of their quantum numbers and electron capacity.
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Homework Statement



The number of electron states in a subshell with orbital quantum number l = 3 is:
A. 7
B. 9
C. 14 <-- answer
D. 2
E. 3

I am reviewing for a comprehensive final and maybe its all the studying but I am lost here..

Homework Equations



n=/=0
l= 0--> (n-1)
m = -l to l

The Attempt at a Solution



Okay so far I have that if l = 3 then m = [-3,...,3] and that n= 4. Do I just add them up 3+7+4 to arrive at the answer? Is this representative of the different combinations? Orbitals are the one subject I consistently have difficulty with in chem/phys. Thanks for your help.
 
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Me too - go back to basics: one electron per |n,l,m,s> state.

for l=3, there are 7 possible values for m, with two spin states each = 14 total.
 

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