1. The problem statement, all variables and given/known data A hot-air balloon has just lifted off and is rising at a constant rate of 2.3m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 14m/s. If the passenger is 2.5m above her friend when the camera is tossed, how high is she when the camera reaches her. 2. Relevant equations Constant linear acceleration equations v=v(i) +a*t x=x(i) + v(i)t + 1/2at^2 3. The attempt at a solution The part of this problem that confuses me is the acceleration of the camera. I know that the acceleration of the balloon is just -9.8 but how can I find the acceleration of the camera without time, etc. I tried solving where x(balloon)= x(camera) but i used -9.8 as the acceleration for both and i do not believe i got the right time. Any help would be great. Thanks.