# One-D Kinematic Question w/ rising hot air balloon

## Homework Statement

A hot-air balloon has just lifted off and is rising at a constant rate of 2.3m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 14m/s.

If the passenger is 2.5m above her friend when the camera is tossed, how high is she when the camera reaches her.

## Homework Equations

Constant linear acceleration equations

v=v(i) +a*t
x=x(i) + v(i)t + 1/2at^2

## The Attempt at a Solution

The part of this problem that confuses me is the acceleration of the camera. I know that the acceleration of the balloon is just -9.8 but how can I find the acceleration of the camera without time, etc. I tried solving where x(balloon)= x(camera) but i used -9.8 as the acceleration for both and i do not believe i got the right time.

Any help would be great.
Thanks.

Doc Al
Mentor
The part of this problem that confuses me is the acceleration of the camera.
The acceleration of the camera is the same as any other body in free fall.
I know that the acceleration of the balloon is just -9.8
No. You are told that the balloon is rising at a constant rate--so what must be its acceleration?

The acceleration of the camera is the same as any other body in free fall.

No. You are told that the balloon is rising at a constant rate--so what must be its acceleration?

zero, ok i understand, i just thought -g would still act on the balloon but it wouldn't

Thanks