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## Homework Statement

A hot-air balloon has just lifted off and is rising at a constant rate of 2.3m/s. Suddenly, one of the passengers realizes she has left her camera on the ground. A friend picks it up and tosses it straight upward with an initial speed of 14m/s.

If the passenger is 2.5m above her friend when the camera is tossed, how high is she when the camera reaches her.

## Homework Equations

Constant linear acceleration equations

v=v(i) +a*t

x=x(i) + v(i)t + 1/2at^2

## The Attempt at a Solution

The part of this problem that confuses me is the acceleration of the camera. I know that the acceleration of the balloon is just -9.8 but how can I find the acceleration of the camera without time, etc. I tried solving where x(balloon)= x(camera) but i used -9.8 as the acceleration for both and i do not believe i got the right time.

Any help would be great.

Thanks.