One Dimentional Relative Motion

  • Thread starter shizaep
  • Start date
  • #1
7
0

Homework Statement



An ocean liner approaches a peer at 20km/h. When the ocean liner is 10 km away, the captain sends a speedboat to the pier to pick up the harbour pilot, who will help dock the ocean liner. The speedboat takes 12 min to get to the pier.
a) How long would the speedboat take to return to the ocean liner if it maintains the same speed?
b)Find the displacement of the speedboat during the round trip and the distance covered by the speedboat during the round trip.

Homework Equations



xab(t) = 1/2 aabt^2 + voab + xoab

The Attempt at a Solution



a) (0) = (0) + (8.33)t + (0)

??
 

Answers and Replies

  • #2
That's not much of an attempt. Do you have any specific questions? What are you getting hung up on?
 
  • #3
7
0
Since relative acceleration is zero, there would only be one solution for t, at 0?
Makes no sense so I definitely did not construct the equation correctly
 
  • #4
I don't think your looking at this right.

Acceleration is constant, so just take that out of your equation.

##x(t)=x_{b0}+v_b(t)##, where##v_b## is the velocity of the ocean liner, if it takes the speedboat 12 minutes to get to the shore how far as the Ocean liner traveled in that time? What is the speedboats velocity? ##v_s={\frac{x}{t}}##, where ##v_s## is the velocity of the speedboat.

Now that should get you started, keep in mind that the Ocean Liner is constantly moving.
 

Related Threads on One Dimentional Relative Motion

Replies
5
Views
1K
Replies
0
Views
3K
  • Last Post
Replies
3
Views
7K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
2
Views
7K
  • Last Post
Replies
2
Views
2K
Replies
8
Views
11K
  • Last Post
Replies
2
Views
2K
Top