One Dimentional Relative Motion

In summary, an ocean liner traveling at 20km/h sends a speedboat to the pier when it reaches a distance of 10km. The speedboat takes 12 minutes to reach the pier and will take the same amount of time to return to the ocean liner. The total displacement of the speedboat during the round trip is 20km and the distance covered by the speedboat during the round trip is 40km. To solve for the return time, we can use the equation x(t) = x0 + v(t), where v is the velocity of the ocean liner.
  • #1
shizaep
7
0

Homework Statement



An ocean liner approaches a peer at 20km/h. When the ocean liner is 10 km away, the captain sends a speedboat to the pier to pick up the harbour pilot, who will help dock the ocean liner. The speedboat takes 12 min to get to the pier.
a) How long would the speedboat take to return to the ocean liner if it maintains the same speed?
b)Find the displacement of the speedboat during the round trip and the distance covered by the speedboat during the round trip.

Homework Equations



xab(t) = 1/2 aabt^2 + voab + xoab

The Attempt at a Solution



a) (0) = (0) + (8.33)t + (0)

??
 
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  • #2
That's not much of an attempt. Do you have any specific questions? What are you getting hung up on?
 
  • #3
Since relative acceleration is zero, there would only be one solution for t, at 0?
Makes no sense so I definitely did not construct the equation correctly
 
  • #4
I don't think your looking at this right.

Acceleration is constant, so just take that out of your equation.

##x(t)=x_{b0}+v_b(t)##, where##v_b## is the velocity of the ocean liner, if it takes the speedboat 12 minutes to get to the shore how far as the Ocean liner traveled in that time? What is the speedboats velocity? ##v_s={\frac{x}{t}}##, where ##v_s## is the velocity of the speedboat.

Now that should get you started, keep in mind that the Ocean Liner is constantly moving.
 
  • #5


b) The displacement of the speedboat during the round trip would be 20 km (10 km away from the ocean liner to the pier, and 10 km back to the ocean liner) in the positive direction. The distance covered by the speedboat during the round trip would be 20 km, as it travels 10 km to the pier and 10 km back to the ocean liner.
 

1. What is one-dimensional relative motion?

One-dimensional relative motion refers to the movement of an object in a straight line in relation to another object. It takes into account the displacement, velocity, and acceleration of both objects.

2. How is one-dimensional relative motion different from one-dimensional motion?

One-dimensional motion refers to the movement of an object in a straight line without considering any other objects. On the other hand, one-dimensional relative motion takes into account the movement of two or more objects in relation to each other.

3. What are the key factors that affect one-dimensional relative motion?

The key factors that affect one-dimensional relative motion include the initial position and velocity of each object, the acceleration of each object, and the time elapsed since the motion began.

4. How is one-dimensional relative motion calculated?

One-dimensional relative motion can be calculated using the equations of motion, such as the displacement equation (d = v0t + 1/2at2), velocity equation (v = v0 + at), and acceleration equation (a = (v - v0)/t). These equations can be applied to each object and their values can be compared to determine their relative motion.

5. What are some real-life examples of one-dimensional relative motion?

Some examples of one-dimensional relative motion include a car traveling on a straight road while passing another car, a person walking on a moving train, and a boat moving towards a dock in a river with a current.

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