Kinematics - identifying and describing types of motion

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SUMMARY

The discussion focuses on identifying and describing types of motion in kinematics, specifically analyzing the motion of a truck. The truck's journey includes segments of varying speeds, leading to the conclusion that it exhibits non-uniform motion due to changes in velocity and direction. Key equations used include average speed and average velocity, with specific calculations provided for total displacement and time. The importance of precise terminology in physics, such as avoiding vague descriptors like "quick" and "slow," is emphasized for clarity in problem-solving.

PREREQUISITES
  • Understanding of kinematic equations, specifically average speed and average velocity.
  • Familiarity with the concepts of displacement and time in motion analysis.
  • Knowledge of uniform versus non-uniform motion.
  • Ability to interpret motion graphs and their slopes.
NEXT STEPS
  • Study the differences between average speed and average velocity in kinematics.
  • Learn how to analyze motion graphs and interpret changes in slope.
  • Explore the concept of constant speed and its application in real-world scenarios.
  • Review examples of non-uniform motion and how to calculate displacement accurately.
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators seeking to clarify concepts of motion and terminology in problem-solving.

alexandria
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Homework Statement


upload_2016-3-21_22-58-51.png


Homework Equations


average speed = total distance/total time
average velocity = total displacement/total time

The Attempt at a Solution


please verify if my answers are correct. Thanks :D
im specifically having doubts about a), i don't know how to identify when the truck moves at a quicker or slower pace. I've placed a star * beside phrases that i feel are incorrect. Please check them out.
23. [/B]

a)

The truck *quickly moved 14.0 km (South) in 15 min. The truck continued another 6 km at a *slower pace over 10 min, and then stayed at this location for 5 min. The truck moved at a *slower pace and continued on for another 8 km towards the destination, taking 15 min for this portion of its journey.

b)

This motion represents non-uniform motion. This can easily be seen, since there are changes in the slope of the graph. This indicates that there are changes in the truck’s velocity and direction. As the truck picks up and delivers a cargo of cabbage, it will need to make turns on to other roads, change direction to take different routes, slow down at stop signs and traffic lights, and speed up to pass stop signs and traffic lights. In this case, the truck is not maintaining a constant velocity and is changing directions, so it is an example of non-uniform motion.

c)

total time = 25 min

total displacement: d = 14.0 km + 6.0 km = 20 km

average velocity = total displacement / total time

average velocity = 20 km / 25 min

average velocity = 0.8 km /mind)

Total displacement = 8.0 km (S)

t = 25 min

Average velocity = total displacement / total time

Average velocity = 8.0 km (S) / 25 min

Average velocity = 0.32 km/min (S)
 
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alexandria said:
The truck *quickly moved 14.0 km (South) in 15 min. The truck continued another 6 km
You might want to think about that again.
Also, I suggest mentioning constant speed, where appropriate.
 
a) You should not use non-quantified words such as "quick" and "slow". Quote the actual speed.

b) You are here mostly describing a real truck, not the one in the graph, which only moves in one direction. Everything after "As the truck" is superfluous and not part of the solution.

c) This is average speed, not average velocity. Please use correct terminology. You also have not distinguished what you call "total displacement" in c from what you call the same in d!
 

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