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## Main Question or Discussion Point

One has to wonder about photon interaction, and when to think of them as a particle and when as simply a wave. A friend of mine told me to think of them as a wave, because they are without mass. But why should I view it that way, when even theoretical mass is mass, such as weak force. So how might one think of them? And what about this:

E=mc^2

Energy of one photon:

E=hv

E=h(c/λ)

E=(4.13566733×10^-15)((299,792,458)/λ)

E=(4.13566733×10^-15)(299,792,458)(1/λ)

E=(4.13566733×10^-15)(299,792,458)(λ^-1)=mc^2

m=((4.13566733×10^-15)(299,792,458)(λ^-1))/(c^2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(1/c^2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(c^-2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(299,792,458^-2)

m=(.00000000000000413566733)(299,792,458)(.0000000000000000111265006)(λ^-1)

m=(1.37951014×10^-23)(λ^-1)

m=(.0000000000000000000000137951014)(λ^-1)

By this logic, and by no means do I claim it to be infallible, photons do have a theoretical mass inversely proportional to its wavelength and multiplied by the constant (1.37951014×10^-23) which I dub, were it to have any scientific ground to it, Demitri constant.

E=mc^2

Energy of one photon:

E=hv

E=h(c/λ)

E=(4.13566733×10^-15)((299,792,458)/λ)

E=(4.13566733×10^-15)(299,792,458)(1/λ)

E=(4.13566733×10^-15)(299,792,458)(λ^-1)=mc^2

m=((4.13566733×10^-15)(299,792,458)(λ^-1))/(c^2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(1/c^2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(c^-2)

m=(4.13566733×10^-15)(299,792,458)(λ^-1)(299,792,458^-2)

m=(.00000000000000413566733)(299,792,458)(.0000000000000000111265006)(λ^-1)

m=(1.37951014×10^-23)(λ^-1)

m=(.0000000000000000000000137951014)(λ^-1)

By this logic, and by no means do I claim it to be infallible, photons do have a theoretical mass inversely proportional to its wavelength and multiplied by the constant (1.37951014×10^-23) which I dub, were it to have any scientific ground to it, Demitri constant.