One two-variable, and one three-variable limits

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SUMMARY

This discussion focuses on evaluating two limits involving multiple variables. The first limit, \mathop {\lim }\limits_{(x,y) \to (0,2)} \frac{{y^2 (x - 2)^2 }}{{x^2 (y - 2)^2 }}, reveals that using curves such as y-2=mx and y-2=kx^2 leads to infinite results. The second limit, \mathop {\lim }\limits_{(x,y,z) \to (0,1,1)} \frac{{y + 1}}{{\sqrt {z^2 - 1} }}, is approached by examining the (y, z)-plane, confirming that the limit can be simplified by focusing on \lim_{(y, z) \to (1, 1)} \frac{y + 2}{\sqrt{z^2 - 1}}.

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1. I need to find these two limits, without using the definition of limit:

a) [tex] \mathop {\lim }\limits_{(x,y) \to (0,2)} \frac{{y^2 (x - 2)^2 }}<br /> {{x^2 (y - 2)^2 }}[/tex]

b) [tex] \mathop {\lim }\limits_{(x,y,z) \to (0,1,1)} \frac{{y + 1}}<br /> {{\sqrt {z^2 - 1} }}[/tex]

The Attempt at a Solution



For a) I found that if looking for the limit using curves, in this case using y-2=mx, with m=constant, and y-2=kx^2, with k=constant, are infinite.

For b) I'm clueless.

Any help will be thanked.
 
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For the second one, note that there is no x-dependency. So you can look at curves in the (y, z)-plane and give them arbitrary x-dependency, i.e. only consider
[tex]\lim_{(y, z) \to (1, 1)} \frac{y + 2}{\sqrt{z^2 - 1}}[/tex]
 
Yes, I was thinking about that, thanks.
 

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