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Only conservative vector fields are path independent?

  1. Aug 4, 2014 #1
    does anyone have a proof of this?
     
  2. jcsd
  3. Aug 4, 2014 #2

    micromass

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    Could you elaborate on your statement? What does it mean for a vector field to be path independent? Could you give the precise statement (which I guess have to do something with integrals over a path). Furthermore, in what generality are you interested? Manifolds, surfaces in ##\mathbb{R}^n##, open subsets of ##\mathbb{R}^2##?
     
  4. Aug 14, 2014 #3

    mathwonk

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