Open and Closed Pipe Length for Harmonics

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Homework Help Overview

The discussion revolves around determining the length of a pipe designed to produce two successive harmonics at specific frequencies (240Hz and 280Hz) in air at 20 degrees Celsius. The problem involves concepts related to harmonics and the characteristics of open and closed pipes.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the definition of harmonics and the relevant formulas, questioning the applicability of certain equations to different types of pipes (open vs. closed).

Discussion Status

Some participants have provided definitions and formulas related to harmonics, while others are seeking clarification on the differences between open and closed pipes. There is an ongoing exploration of the problem without a clear consensus on the approach to take.

Contextual Notes

There is a noted lack of information regarding the specific characteristics of the pipe (open or closed) and how this affects the calculation of its length for the desired harmonics.

SUXinPHY
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Homework Statement



a pipe in air at 20 degrees celsius ia to be designed to produce two succesive harmonics at 240Hz & 280Hz. how long must the pipe be, and is it open or closed?

Homework Equations



v=\lambdaf


The Attempt at a Solution



sorry, i could not do it. i totally can't do it.
 
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SUXinPHY said:

Homework Statement



a pipe in air at 20 degrees celsius ia to be designed to produce two succesive harmonics at 240Hz & 280Hz. how long must the pipe be, and is it open or closed?

Homework Equations



v=\lambdaf


The Attempt at a Solution



sorry, i could not do it. i totally can't do it.
Can you start by telling me what a harmonic is?
 
harmonics are frequencies of a wave which consits the fundamental frequency.

the formula for fundamental harmonic is

fn
= v/\lambdan
= n (v/2L)
= nf0
 
SUXinPHY said:
harmonics are frequencies of a wave which consits the fundamental frequency.
Correct.
SUXinPHY said:
the formula for fundamental harmonic is

fn
= v/\lambdan
= n (v/2L)
= nf0
That equation is only valid for tubes with open ends, what about tubes with closed ends?
 

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