Find Wavelength of 8cm Closed Pipe: 7th Harmonic

[ThePhysicsXV]

Homework Statement

What is the wavelength of an 8cm closed pipe when it is sounding the 7th harmonic?

Homework Equations

L=λn/4

The Attempt at a Solution

L=(.08m*7)/(4)
L=0.14m
Am I correct?

 

[drvrm]

L=(.08m*7)/(4)
L=0.14m
Am I correct?

check your calculation-are you finding out the pipe length or wavelength?

 

[ThePhysicsXV]

check your calculation-are you finding out the pipe length or wavelength?

Wavelength

 

[ThePhysicsXV]

check your calculation-are you finding out the pipe length or wavelength?

Oh yeah wavelength, so is
λ=4L/n
λ=4(.08)/7
Since is 7th harmonic.
λ= .045m

 

[drvrm]

Oh yeah wavelength, so is
λ=4L/n
λ=4(.08)/7
Since is 7th harmonic.
λ= .045m

I think its correct!

 

[BvU]

Seems a bit small to me. Is the pipe closed on both ends ? Can you check your relevant equation? Where does it come from ? Do you understand it ? Can you make a drawing ?

[edit] I was mistaken. Your answer is right for a pipe that is closed on one end and open on the other.