Opposite Induced Currents in Circuit Explanation

AI Thread Summary
The discussion clarifies that the induced currents in a circuit formed by rods and rails flow in opposite directions, with one being clockwise and the other anticlockwise, resulting in no net current. It emphasizes that if both currents were to flow in the same direction, it would contradict the requirement for current to circulate around the circuit. The induced electromotive force (emf) in each rod is aligned, leading to cancellation of the emfs, similar to connecting two batteries in opposition. Consequently, the total emf in the circuit becomes zero, preventing any current from flowing. Understanding this principle is crucial for grasping the behavior of induced currents in circuits.
ellieee
Messages
78
Reaction score
6
Homework Statement
would there be induced current in rods PQ and RS?
Relevant Equations
nil
I don't understand why they said that the induced current flow is opposite to each other when it clearly states direction is to the right for both? https://www.physicsforums.com/attachments/285900
 

Attachments

  • 16261850189355184978004148639225.jpg
    16261850189355184978004148639225.jpg
    42.8 KB · Views: 116
Physics news on Phys.org
It's not quite clear (what is the experiment that is repeated?), but I think it means that if you consider the circuit formed by the rods and rails, the induced current in PQ is clockwise, and that in RS is anticlockwise, i.e. the opposite direction around the circuit, so there is no net current in the circuit.
 
Imagine a circuit where the current along the top line is L-R and the current along the bottom line is also L-R. It can't happen, because the current needs to flow around the circuit so must flow in the opposite direction in the top and bottom of the circuit.

So, in this case, the emf induced in each rod is in the same direction, so there can be no current because the emfs are cancelling each other out (like connecting two batteries facing each other) so the total emf in the circuit is zero.
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top