Opposite Induced Currents in Circuit Explanation

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The discussion clarifies that the induced currents in a circuit formed by rods and rails flow in opposite directions, with one being clockwise and the other anticlockwise, resulting in no net current. It emphasizes that if both currents were to flow in the same direction, it would contradict the requirement for current to circulate around the circuit. The induced electromotive force (emf) in each rod is aligned, leading to cancellation of the emfs, similar to connecting two batteries in opposition. Consequently, the total emf in the circuit becomes zero, preventing any current from flowing. Understanding this principle is crucial for grasping the behavior of induced currents in circuits.
ellieee
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Homework Statement
would there be induced current in rods PQ and RS?
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I don't understand why they said that the induced current flow is opposite to each other when it clearly states direction is to the right for both? https://www.physicsforums.com/attachments/285900
 

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It's not quite clear (what is the experiment that is repeated?), but I think it means that if you consider the circuit formed by the rods and rails, the induced current in PQ is clockwise, and that in RS is anticlockwise, i.e. the opposite direction around the circuit, so there is no net current in the circuit.
 
Imagine a circuit where the current along the top line is L-R and the current along the bottom line is also L-R. It can't happen, because the current needs to flow around the circuit so must flow in the opposite direction in the top and bottom of the circuit.

So, in this case, the emf induced in each rod is in the same direction, so there can be no current because the emfs are cancelling each other out (like connecting two batteries facing each other) so the total emf in the circuit is zero.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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