Optics Experiment 1: Determining Index of Refraction & Wavelength

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The experiment aims to determine the index of refraction of a transparent plastic block using a laser and a diffraction grating. The procedure involves creating an interference pattern on a screen, marking the central and first-order bright spots, and measuring the angle of diffraction. The wavelength of the light source is essential, as the index of refraction varies with wavelength. The relationship between path difference and angles in Young's Two Slit Experiment is applicable here, as it uses the same equation for maxima. Ultimately, the experiment combines these principles to calculate the refractive index based on observed shifts in the interference pattern.
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1. You are given the following equipment for use in the optics experiments in parts (a) and (b).
- A solid rectangular block made of transparent plastic
- A laser that produces a narrow, bright, monochromatic ray of light
- A protractor
- A meter stick
- A diffraction grating of known slit spacing
- A white opaque screen

(a) Briefly describe the procedure you would use to determine the index of refraction of the plastic. Diagram?

(b) Since the index of refraction depends on wavelength, you need to determine the wavelength of your light source.
2. Dark Slits vs. Bright Slits
c=fλ
Path Difference: Δl = dsinθ
Bright Fringe: dsinθ =mλ
Dark Fringe: dsinθ = (m-1/2)λ




3. Does this all have to do with Young's Two Slit Experiment? Setting up something that will create an interference pattern and then using that to determine other things..?
 
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pfforum said:
Does this all have to do with Young's Two Slit Experiment? Setting up something that will create an interference pattern and then using that to determine other things..?

Yes. The equation d*sin(theta) = m*lamda that gives the maxima for Young's experiment is the same equation for a diffraction grating.

Your problem is to determine the index of refraction of the plastic. Here are some key questions you need to answer. What happens to the wavelength of light when you pass it through some material other than a vacuum? What is the behavior among wavelength and the angles associated with maxima in Young's interference experiment?
 
Using diffraction grating form the interference pattern on the white screen. Mark the central and first order bright spot. Draw a perpendicular from central bright spot to position of the grating. Join the point of intersection of these to to the first order bright spot. That gives you the angle θ. Now place the plastic block in the path of the ray and parallel to the screen. Mark the new position of the first order bright spot. From this point draw a parallel line to the initial path of the ray. Find the distance between them. That is the lateral shift. Find the expression for the lateral from any book and find refractive index of the plastic slab.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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