Optics: Half Lens in the Air, Half Lens in Water.

[Steveyudea]

Homework Statement

Hello everybody! One surface of a biconvex lens (n=1,5) is in the air (n_a=1) while the other surface is dipped in the water (n_w=4/3). If the power of the lens in the air is P_o=10 Dioptri, The lens power in such condition is?

Homework Equations

Lensmaker Equation
P_l=((n₂/n₁)-1).{(1/R₁)-(1/R₂)}

The Attempt at a Solution

I've tried to derived the lensmaker equation for three medium using geometry resulting in (P=[n₁/d_o]+[n₃/d_i]). Since there is no given distance of object nor distance of the image, I do not know how to work this problem out.

 

[haruspex]

Homework Statement

Hello everybody! One surface of a biconvex lens (n=1,5) is in the air (n_a=1) while the other surface is dipped in the water (n_w=4/3). If the power of the lens in the air is P_o=10 Dioptri, The lens power in such condition is?

Homework Equations

Lensmaker Equation
P_l=((n₂/n₁)-1).{(1/R₁)-(1/R₂)}

The Attempt at a Solution

I've tried to derived the lensmaker equation for three medium using geometry resulting in (P=[n₁/d_o]+[n₃/d_i]). Since there is no given distance of object nor distance of the image, I do not know how to work this problem out.

Try considering the lens as two planoconvex lenses together. Do you know how to calculate the power of two lenses in series?