(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Call the irradiance at the center of the central Fraunhofer diffraction maximum of a single slit [itex]I_0[/itex] and the irradiance at some other point in the patterm I. Obtain the ratio [itex]I/I_0[/itex] for some point on the screen that is 3/4 of a wavelength farther from one edge of the slit than the other.

2. Relevant equations

Irradiance for single slit diffraction

[tex]I=I_0sinc^2(β)[/tex]

[tex]β=\frac{1}{2}kbsin\theta[/tex]

[tex]k=\frac{2\pi}{\lambda}[/tex]

b=slit size

3. The attempt at a solution

Well I know that when beta is equal to zero, the irradiance is at its maximum. But I do not know if this helps me or not. I honestly do not understand the question. 3/4 of a wavelength farther from one edge of the slit than the other? Don't I need the slit length? How can I make use of this information? Why does it say "than the other." What other point?

I really want to understand this problem. If anyone can help me I would much appreciate it!

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# Homework Help: Optics: I do not understand what this question is asking!

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