Optics- Total internal reflection

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SUMMARY

The discussion centers on calculating the refractive index of a rectangular glass slab, 2.25 cm thick, based on the phenomenon of total internal reflection. A light source at the bottom emits rays that create a circle of 7.6 cm in diameter on the bottom surface due to total internal reflection at the top surface. The participant seeks assistance in determining the angle of incidence and reflection, referred to as theta 1, to proceed with the calculation of the refractive index.

PREREQUISITES
  • Understanding of Snell's Law and refraction principles
  • Knowledge of total internal reflection concepts
  • Familiarity with geometric optics and ray diagrams
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Calculate the angle of incidence using the geometry of the setup
  • Research the formula for calculating refractive index from critical angle
  • Explore the relationship between diameter of the circle and angle of incidence
  • Study examples of total internal reflection in different mediums
USEFUL FOR

Students and educators in physics, optical engineers, and anyone interested in the principles of light behavior in different materials.

johndoe
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A small source of light at the bottom face of a rectangular glass slab 2.25 cm thick is viewed from above. Rays of light totally internally reflected at the top of the surface outline a circle of 7.6cm in diameter in the bottom surface. Determine the refraction index of the glass.

This is what I interpreted:
4282591097_120b368ae5_o.jpg


I can find out the angle of incidence and reflection (theta 1), but then I am stuck. please help.
 
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My understanding is that the light source is at the bottom. Light is emitted, strikes the top surface where it is reflected at some angle, and returns to the bottom surface. The light source and 7.6 cm circle are both at the bottom surface.

The words "viewed from above" seem misleading and irrelevant.
 

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