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A_Munk3y
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Homework Statement
The owner of a luxury motor yacht that sails among the 4000 Greek islands charges $600 per person per day if exactly 20 people sign up for the cruise. However, if more than 20 people sign up (up to the maximum capacity of 90) for the cruise, then each fare is reduced by $4 for each additional passenger.(a) Assuming at least 20 people sign up for the cruise, determine how many passengers will result in the maximum revenue for the owner of the yacht.
passengers
(b) What is the maximum revenue? (c) What would be the fare/passenger in this case? (Give your answer correct to the nearest dollar.)
The Attempt at a Solution
No idea, could you just help me out on how to even start this problem? Cause i am clueless...
i did it this way, but did not really use optimization i think.
N= # of passengers
600-4N= fare
Revenue= 600N-4N2
max at -> derivative of 0=600N-4N2
0=600-8N
N=600/8
N=75 passengers
600-4(75)= 300$ a passenger
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