Optimizing Lever Mechanics for Lifting Heavy Objects

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Homework Help Overview

The discussion revolves around a physics problem involving levers and mechanics, specifically focusing on the scenario where a young boy attempts to lift a heavy boulder using a lever system. The problem provides specific masses and distances related to the lever setup.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the principles of levers and torque, questioning how to set up the problem correctly. There is discussion about equating torques to find the necessary length of the lever arm for the boy to lift the boulder.

Discussion Status

Some participants have offered guidance on the principles of levers, while others have attempted calculations based on the provided information. There appears to be a mix of understanding and uncertainty regarding the application of torque in this context.

Contextual Notes

Participants note that they have just started learning about levers and have not yet covered torque in detail, which may affect their understanding of the problem.

Kogsug
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I can't figure this problem out and i don't know where to start.

A young boy(50kg) wants to lift a boulder with a mass of 2500kg. He can wedge a board under it so that from the boulder to a pivot/fulcrum is 0.6 meters. How long does the other end of the board have to be for the boy to lift the boulder.

Any ideas?
 
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What principles apply here? (See, this is why you should use the Homework Posting Template that is provided when you start a new homework thread. It should not be considered optional.)

Tell us what you know about levers and fulcrums and maybe even torques. You must show us your work in order to get our help (PF rules).
 
you know your origin, right?
does it make sense that if you set the persons torque equal to the boulder's torque you would be able to solve this problem?
 
what do u mean what principles apply here? this is the full problem word for word. we just started levers... and we have not done torgue.

does this work?

(B)(x)=(0.6m)(load)

(50kg)(x)=(0.6m)(2500kg)

x={(0.6m)(2500kg)}/(50kg)

so x=30 meters?

can someone please tell me if this is right?
 
Last edited:
Looks good to me.
 
ok then... thank you
 

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