Optimizing Rectangle Dimensions within a Circle

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SUMMARY

The discussion focuses on optimizing the dimensions of a rectangle with the largest area that can be inscribed within a circle defined by the equation x² + y² = 4. The area A of the rectangle is expressed as A = 2y * 2√(4 - y²), leading to the derivative dA/dy = 4(-y²/√(4 - y²) + √(4 - y²)). The optimal solution reveals that the rectangle is a square, with its diagonals intersecting at the circle's center, and the side length of the square is determined to be 2√2 units.

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1. Find the dimensions of the rectangle with largest area which can be cut from a circle with equation x^2+ y^2= 4

this is the question but i got stuck half way when i was differentiating the equation

how do i work this out :
[square root of (4-y^2)] + ([-y ^2] \ square root[ 4- y^2])
 
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So if A represents the area of the rectangle, you have [tex]\frac{dA}{dy}=4(\frac{-y^2}{\sqrt{4-y^2}}+\sqrt{4-y^2})[/tex].

If you observe the expression, is there something you can factorize that will make it easier to solve for y when you set [tex]\frac{dA}{dy}=0[/tex]?
 
Actually, from symmetry you can argue that the required rectangle has to be a square (special case of a rectangle) whose diagonals meet at the centre of the circle of radius 2 units .
What can you say about the length of the side of this square ?
Hint:Draw radii to the corners of the square .

Of course if the symmetry isn't apparent, you can always go for the calculus approach, which involves setting up coordinate axes and maximising .
 

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