Orbital Angular Momentum and Uncertainty?

Click For Summary
The discussion centers on the relationship between the Uncertainty Principle and orbital angular momentum in quantum mechanics. It explains that the Uncertainty Principle is mathematically grounded, particularly in the context of probability densities and their Fourier transforms. Orbital angular momentum can only take on discrete values, specifically integer multiples of Planck's constant (h). The commutation relations for orbital angular momentum indicate that knowing one component (Lz) leads to uncertainty in the others (Lx and Ly). This highlights the inherent uncertainties in measuring angular momentum components in quantum systems.
LarryS
Gold Member
Messages
359
Reaction score
33
The Uncertainty Principle is largely mathematical. For any two probability densities, if one is the Fourier Transform/Inverse Fourier Transform of the other, then the product of their variances is always greater than zero. Thus, energy and time, and momentum and position, via the squared modulus of their wave functions are related in this manner. But how does orbital angular momentum (not spin) fit into the above picture? It is my understanding that orbital angular momentum can only take on values that are integer multiples of h. As always, thanks in advance.
 
Physics news on Phys.org
If we have a commutation relation of the form
[A,B] = iC
Then we have an uncertainty relation
dAdB >= |<C>| / 2

The relevant commutation relations for orbital angular momentum are
[Lx,Ly] = ihLz
[Ly,Lz] = ihLx
[Lz,Lx] = ihLy

Which leads to uncertainty relations for the orbital angular momentum in different direction. If we know Lz perfectly, then there is uncertainty regarding the values of Lx and Ly.
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
893
  • · Replies 28 ·
Replies
28
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
2K