Orbital Angular Momentum of the Sun-Jupiter System

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SUMMARY

The discussion centers on calculating the orbital angular momentum of the Sun-Jupiter system using the equation L = μ√[GMa(1-e²)]. Participants clarify that the semi-major axis 'a' should refer to Jupiter's orbit around the Sun, not the reduced mass. The conversation emphasizes that the Sun and Jupiter revolve around their common center of mass, and the simplistic Keplerian approach is inadequate for non-circular orbits. The correct approach involves using the average of the apogee and perigee distances to determine the orbital characteristics accurately.

PREREQUISITES
  • Understanding of orbital mechanics and angular momentum
  • Familiarity with Kepler's laws of planetary motion
  • Knowledge of gravitational constants and their applications
  • Basic concepts of elliptical orbits and center of mass
NEXT STEPS
  • Study the derivation of the angular momentum formula L = μ√[GMa(1-e²)]
  • Learn about the dynamics of two-body systems and their center of mass
  • Explore the implications of non-circular orbits in celestial mechanics
  • Investigate the use of averaging techniques in orbital calculations
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Astronomy students, astrophysicists, and educators involved in teaching orbital mechanics and celestial dynamics.

jinksys
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Homework Statement


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In part A I know that I must use L = mu*Sqrt[GMa(1-e^2)], but for the variable 'a' do I use the semi-major axis of Jupiter or the semi-major axis of the reduced mass?

Homework Equations


The Attempt at a Solution

 
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I don't know how you got that equation. This question does not require reduced mass concept. The Sun is stationary and Jupiter revolves around it.

Use L=mvr
substitute v from the equation T=2(pi)r/v
Now the r is actually the average of the radius at apogee and perigee.
i.e. r=(ra + rp)/2
Use properties of ellipse to find the unknown from the above equation.
If you have the mass of Jupiter you are done with the question.
 
Abdul Quadeer said:
I don't know how you got that equation. This question does not require reduced mass concept. The Sun is stationary and Jupiter revolves around it.
This is wrong. The question is rather explicitly asking the student to consider the problem of a non-circular orbit of an object with enough mass that the simplistic Keplerian approach is no longer valid.


jinksys said:
In part A I know that I must use L = mu*Sqrt[GMa(1-e^2)], but for the variable 'a' do I use the semi-major axis of Jupiter or the semi-major axis of the reduced mass?
How do you know that that is the equation you need to use?

Hint: Depending on what you mean by the "semi major axis of Jupiter", this is also wrong.

The question is a bit sloppy in that it doesn't say what that 5.2 AU means. The usual meaning is in terms of Jupiter's orbit about the Sun rather than Jupiter's orbit about the barycenter.
 
D H said:
This is wrong. The question is rather explicitly asking the student to consider the problem of a non-circular orbit of an object with enough mass that the simplistic Keplerian approach is no longer valid.

Can you explain me what is wrong?
Is there any problem with averaging the radius? Does the Sun + Jupiter revolve around their common centre of mass?
 
Abdul Quadeer said:
Can you explain me what is wrong?
Is there any problem with averaging the radius?
Yes,there is. You can't average the the radius and then assume as you said that "T=2(pi)r/v".

Does the Sun + Jupiter revolve around their common centre of mass?
Yes, they do.
 
I think I have misunderstood something.
This is a question in my book-
A planet is revolving around the sun. Its distance from the sun at apogee is Ra and that at perigee is Rp. The mass of the planet and sun is m and M resp, T is the time period of revolution of planet round the sun. What is the relation between T,M, Ra and Rp?

The answer given is T2 = π2(Ra + Rp)3/2GM, which is obtained by averaging the radius.

Is the answer given wrong? If yes then what laws should we use to find the relation?
 

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