Orbital Perturbations: Solving for Equations of Motion in Elliptical Orbits

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SUMMARY

The discussion focuses on determining the new orbit of a planet after a small radial push in a circular orbit around a star. The relevant equations include Kepler's orbital radius, expressed as r(φ)=c/(1+εcos(φ)), and the orbital energy equation E=(γ^2)μ((ε^2)-1)/(2L^2). The hypothesis suggests that the new orbit will be elliptical, and the participant proposes using a Taylor expansion to derive the new equations of motion. It is concluded that while the radial push does not change angular momentum, it alters the orbital energy, allowing for the computation of the new eccentricity.

PREREQUISITES
  • Understanding of Kepler's laws of planetary motion
  • Familiarity with orbital mechanics and equations of motion
  • Knowledge of Taylor series expansions
  • Basic principles of angular momentum and energy in orbital dynamics
NEXT STEPS
  • Study the derivation of elliptical orbits from circular orbits in classical mechanics
  • Learn about the implications of radial forces on orbital parameters
  • Explore the application of Taylor series in physics for approximating functions
  • Investigate the relationship between orbital energy and eccentricity in celestial mechanics
USEFUL FOR

Astronomy students, astrophysicists, and anyone studying orbital dynamics and perturbations in celestial mechanics will benefit from this discussion.

Konchock Dawa
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Homework Statement


Say I have some planet in a circular orbit around a star, and I give it a small radial push (directly toward or directly away from the star). How would I describe the new orbit? I.e. how would I determine the equations of motion? h

Homework Equations


Kepler orbital radius: r(φ)=c/(1+εcos(φ)) where c=(L^2)/(γμ).

Also possibly relevant, orbital energy: E=(γ^2)μ((ε^2)-1)/(2L^2)

The Attempt at a Solution



My intuitive hypothesis is that the new orbit should be elliptical. A circular orbit has constant radius r(φ)=c, and we have already proved in this class that the radius after a small push will oscillate with a period equal to the orbital period, so it seems like if we just add a sinusoidal term, r(φ)=c+Asin(φ) we should be able to get the equation in the elliptical form r(φ)=c/(1+εcos(φ)) but that doesn't seem to work. I have a hunch that I'm supposed to do some sort of a Taylor expansion, but I don't know which function I would expand. It also seems like, since a push would change the angular momentum L, we should be able to replace L with L+δ and again get something of the form r(φ)=c/(1+εcos(φ)). Is any of this heading in the right direction? Have spent many hours on this problem and could use a hint.
 
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If the push is radial, then I think it won't change the angular momentum. A radial force does not result in any torque, and if there is no torque, there can be no change in angular momentum. So only the orbital energy will change. If you assume E changes and L does not, then you can compute the new value of eccentricity.
 
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