Orbits: explicit r(t) and theta(t)

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The discussion focuses on deriving the equations for r(t) and theta(t) in the context of orbits governed by an inverse square law, with the central mass treated as at rest. The main equation provided is r = a(1-e^2)/(1+e cos(theta), which describes the orbit's shape but does not explicitly show time evolution. While an explicit form for the mean anomaly M(t) exists, it is simple and expressed as M(t) = M(t0) + (t-t0) dot M. The relationship between the mean anomaly and eccentric anomaly is established through Kepler's equation, and the eccentric anomaly is linked to the true anomaly via a tangent relationship. The thread highlights the complexity of explicitly expressing time evolution in orbital mechanics.
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I am sure this is a stupid question but can someone give me the equations for r(t) and theta(t) for an orbit an inverse square law (treating the central mass as being at rest). The books always seem to only give r(theta) i.e. the shape of the orbit but not the actual time evolution. Is it ever done explicitly?

thanks
 
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A more proper treatment is treating the center of mass as being at rest. If the orbiting body is of negligible mass, the central mass will essentially be at rest.

You are most likely talking about the equation

r=\frac{a(1-e^2)}{1+e\cos\theta}

where \theta is the true anomaly. The time evolution in terms of \theta does not have an explicit form.

An explicit form for the time evolution of the mean anomaly does exist, and it is quite simple in form:

M(t)=M(t_0) + (t-t_0)\dot M

The mean anomaly is related to the eccentric anomaly \psi via Kepler's equation:

M(t) = \psi(t) - e\sin\psi(t)

The eccentric anomaly is in turn related to the true anomaly by

\sqrt{1-e}\tan\frac{\theta}2 = \sqrt{1+e}\tan \frac{\psi(t)}2
 
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