Order by asymptotic growth rate

[dba]

Homework Statement

I try to order given functions and I am stuck with evaluating the following:

f(n)= (n+1)! and g(n)=n^{logn}

Homework Equations

\lim_{n\to\infty}\frac{f(n)}{g(n)} = 0

then g(n) is faster growing.

\lim_{n\to\infty}\frac{f(n)}{g(n)} = \infty

then f(n) is faster growing.

The Attempt at a Solution

I would guess that n^{logn} is the faster growing function because it is exponential.
Thus, I write
\lim_{n\to\infty}\frac{(n+1)!}{n^{logn}} and would expect the result to be zero.

My problem is that I do not know hot to take the limit of a factorial function and I also have a problem with the n^logn.
Can someone help me with this? Maybe I can write the functions in a different way?

Thanks for any help.

 

[Ninty64]

Edit: Nevermind. Now I'm curious though.

[STRIKE]I might just be going out on a limb here, but I think that looking at it from this perspective might help:

By the definition of logarithm,
log_{10}n = x
implies
n = 10^x

I hope it helps at least[/STRIKE]