Given H,K and general finite subgroups of G,(adsbygoogle = window.adsbygoogle || []).push({});

ord(HK) = [(ord(H))(ord(K))] / ord(H intersection K)

I know by the first isomorphism theorem that Isomorphic groups have the same order, but the left hand side of the equation is not a group is it?

I am struggling to show this.

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# Order of groups in relation to the First Isomorphism Theorem.

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