Given H,K and general finite subgroups of G,(adsbygoogle = window.adsbygoogle || []).push({});

ord(HK) = [(ord(H))(ord(K))] / ord(H intersection K)

I know by the first isomorphism theorem that Isomorphic groups have the same order, but the left hand side of the equation is not a group is it?

I am struggling to show this.

**Physics Forums | Science Articles, Homework Help, Discussion**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Order of groups in relation to the First Isomorphism Theorem.

Loading...

Similar Threads for Order groups relation |
---|

I Spin group SU(2) and SO(3) |

I What is difference between transformations and automorphisms |

I Lorentz group representations |

I Correspondence Theorem for Groups ... Another Question ... |

**Physics Forums | Science Articles, Homework Help, Discussion**