Ordered Pairs in Relation A to B

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Homework Help Overview

The problem involves listing ordered pairs in a relation R defined between two sets A and B, with specific conditions regarding the pairs. The subject area includes concepts of relations, ordered pairs, and properties such as least common multiple and greatest common divisor.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the conditions for forming ordered pairs based on the given inequalities and mathematical properties. Some attempt to clarify specific conditions, while others express confusion about how to apply them.

Discussion Status

The discussion is ongoing, with participants providing examples for certain conditions and seeking further clarification on others. There is a mix of understanding and uncertainty, particularly regarding the interpretation of the conditions.

Contextual Notes

Participants note the complexity introduced by the multiple conditions, indicating a need for further exploration of each condition's implications on the ordered pairs.

bird34
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Homework Statement



List the ordered pairs in the relation R from A = {1, 2, 3, 5} to B = {2, 4, 6, 9} where <x, y> is an element of R iff:

(i) x ≥ y
(ii) x – y < 2
(iii) x – y > 2
(iv) l.c.m. (x, y) = 18
(v) g.c.d. (x, y) = 3


I understand in general ordered pairs and cartesian products, but I'm not sure where to begin when there are limitations such as these.
 
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welcome to pf!

hi bird34! welcome to pf! :wink:

(you understand they're alternatives?)

what's the difficulty?

eg for (ii), R = {(5,9),(5,6),(5,4)…}
 
I guess maybe I don't understand after all. I get where the numbers came from for (ii), but what about the others ones? I'm lost and need an explanation. Thanks!
 
for (ii), R is the set of all ordered pairs (x,y) such that x - y < 2

so eg 5 - 4 < 2, so (5,4) is in

but 5 - 2 =3, so (5,2) is out :wink:
 
Ok, so for (iii), the answer would only be {5,2}?
 
And for (i) it would be R = {2,2}, {3,2}, {5,2}, {5,4}?

If so, I feel like an idiot for overlooking the simplicity in this!
By the way, do you know anything about a digraph?
 
bird34 said:
And for (i) it would be R = {2,2}, {3,2}, {5,2}, {5,4}?

yup! :biggrin:
By the way, do you know anything about a digraph?

no, we never did them
bird34 said:
Ok, so for (iii), the answer would only be {5,2}?

well, that's the only one with x = 5
 

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