Ordinary and covaraint derivative

  • Context: Graduate 
  • Thread starter Thread starter world line
  • Start date Start date
  • Tags Tags
    Derivative
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 2K views
world line
Messages
8
Reaction score
0
Hello
what is the meaning of covaraint derivative ?
where the ordinary derivative of a function whit respect to a variable is zero, it means that function doesn't depend on that variable.but what about covaraint derivative ?
for example the metric tensor may depends on coordinate but its covaraint derivative is zero.
 
Physics news on Phys.org
The classical (directional) derivative is dependent on your choice of coordinates. The covariant derivative is not; is it covariant in the sense that it is defined in such a way as to be independent of its description in a particular coordinate system. That is why it is written as a directional derivative plus a term that compensates for any changes in coordinates, expressed through the Christoffel Symbols. It is basically a generalization of the classical derivative into Riemann geometry.