Ordinary Differential Equations

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SUMMARY

The discussion focuses on solving the ordinary differential equation (ODE) given by x²y'' + xy' + 9y = -tan(3ln(x)) using the method of variation of parameters. The homogeneous solutions are identified as y₁(x) = cos(3ln(x)) and y₂(x) = sin(3ln(x)). The Wronskian is calculated as W[y₁, y₂] = 3/x. The user encounters difficulties in evaluating the integral for the particular solution, particularly with the term involving y₁(x) and the integral of sin²(3ln(x)). The need to adjust g(x) to g(x) = -tan(3ln(x))/x² is also highlighted for proper application of the variation of parameters method.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with the method of variation of parameters
  • Knowledge of Wronskian determinants in the context of ODEs
  • Basic integration techniques involving trigonometric functions
NEXT STEPS
  • Study the method of variation of parameters in depth
  • Learn how to compute the Wronskian for systems of ODEs
  • Explore integration techniques for trigonometric functions, particularly involving logarithmic arguments
  • Practice solving Euler-Cauchy equations and their applications
USEFUL FOR

Students and educators in mathematics, particularly those studying differential equations, as well as anyone seeking to enhance their problem-solving skills in ODEs using variation of parameters.

NeoDevin
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Homework Statement


Use variation of parameters to find the general solution of:

x^2 y'' + xy' + 9y = -tan(3ln(x))


Homework Equations



y_p = y_2 (x) \int \frac{y_1 (x) g(x)}{W[y_1 (x),y_2 (x)]} dx - y_1 (x) \int \frac{y_2 (x) g(x)}{W[y_1 (x),y_2 (x)]} dx

The Attempt at a Solution



Solution for the homogeneous Euler equation is given by
<br /> y_1 (x) = cos(3ln(x)), y_2 (x) = sin(3ln(x))<br />

I try using these solutions in the equation for variation of parameters with:
W[y_1 , y_2] = \frac{3}{x}
g(x) = -tan(3ln(x))

The first term I can evaluate, but the second term gives me:
y_1 (x) \int \frac{x sin^2 (3ln(x))}{3 cos(3ln(x))} dx

which doesn't seem solvable by any methods I know...

Any suggestions on what to do from here, or where I went wrong on the way would be helpful.
 
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You have to set it up as y" +... to use your variation of parameters formula
 
so the solutions for the homogeneous equation are the same, right? but I need to divide through by x^2 before I apply the formula? so
g(x) becomes:

g(x) = -\frac{tan(3ln(x))}{x^2}
 

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