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i've got unsolved solution here..

Solve initial value problem..

xy’ – y = 2x2y ; y(1) = 1

x dy/dx = y + 2x2y

dy/dx = y/x + 2xy

dy/dx = y[(1/x) + 2x]

∫1/y dy = ∫ (1/x) + 2x dx

ln |y| = ln |x| + x2 + C

apply exp to both side

y = x + ex^2 + e^C

substitute the initial value

1 = 1 + e1 + e^C

e^(1+C) = 0

apply ln

1 + C = ln 0?