Orthochronous Lorentz Transformations

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SUMMARY

The discussion centers on the existence of an orthochronous Lorentz transformation (LT) L such that Lx = -x for vectors x with x² < 0. The participants conclude that for the specific example xµ = (1,0,0,0), the transformation fails to satisfy the condition due to the requirement that Λ00 ≥ 1. The conversation suggests exploring the explicit formula for the Lorentz transformation in 1+1 dimensions, represented as Λ = γ(1, -v; -v, 1), where γ = 1/√(1-v²), while also considering the possibility of satisfying the condition in higher dimensions (2+1 and 3+1).

PREREQUISITES
  • Understanding of Lorentz transformations and their properties
  • Familiarity with the concept of spacetime intervals and metrics
  • Knowledge of special relativity principles
  • Basic linear algebra, particularly matrix operations
NEXT STEPS
  • Explore the derivation and implications of the Lorentz transformation matrix in 1+1 dimensions
  • Investigate the behavior of orthochronous Lorentz transformations in 2+1 and 3+1 dimensions
  • Study the properties of spacetime intervals in special relativity
  • Examine the role of the metric signature in determining transformation properties
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Physicists, mathematicians, and students of relativity who are interested in the mathematical foundations of Lorentz transformations and their applications in theoretical physics.

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How can I convince myself of the following statement:

If x2<0, there exists L orthochronous Lorentz tranformation such that:

Lx = -x

My concern is this:

If for example, we take xµ=(1,0,0,0), then Lx in component form is:

Λµβxβµ0x0
=(Λ00, Λ10, Λ20, Λ30).

By definition, if it is an orthochronous LT, we must have Λ00≥1 so it is clear that the statement above is false for this example (as the RHS in the case of our example vector, can't be positive).

Can anyone think of an example xµ that would actually satisfy the condition Lx = -x?
 
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You're asking the first question in a way that strongly suggests that the statement is supposed to be true for any x with x2<0. (And the fact that you tried x=(1,0,0,0) must mean that you're using a -++++ metric). But Λµβxβ=(Λ00x0,0,0,0) proves that the statement is false.

Are you really looking for a specific choice of Λ and x such that Λx=-x? It looks impossible to me, but I haven't proved it. I suggest that you try playing around with the explict formula for Λ in 1+1 dimensions:

[tex]\Lambda=\gamma\begin{pmatrix}1 & -v\\ -v & 1\end{pmatrix}[/tex]

[tex]\gamma=\frac{1}{\sqrt{1-v^2}}[/tex]

(This is in units such that c=1).

Hm...or maybe not. Maybe it won't work in 1+1 dimensions but will work in 2+1 and 3+1 because then you will have the opportunity to flip the sign of two spatial components with a rotation.
 

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