What is the origin of the minus sign in the derivatives of an oscillating body?

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SUMMARY

The discussion centers on the derivatives of the position function s(t) for an oscillating body, specifically addressing the origin of the negative sign in the second derivative. The first derivative is correctly identified as v = Aωcos(ωt), while the second derivative is -Aω²sin(ωt). The negative sign arises from the properties of the sine function, which indicates the direction of acceleration in harmonic motion. This is a fundamental aspect of classical mechanics related to oscillatory motion.

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Homework Statement
Body of mass 0.2kg is oscillating. A = 5cm , w=π rad/s , t = 1/6 s. Find the force and momentum.
Relevant Equations
s(t) = Asin(wt)
I know it is a quite simple task.
p = mv and F=ma.
All i need to do is find the normal and double derivatives of s(t). But here's the problem , i have the answers and they state that first derivative is v =
-Awcoswt and second is -Aw^2sinwt. Everything is quite clear to me, but I am wondering can someone explain where the minus before A comes from?
 
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It's a mistake, ##\frac{ds(t)}{dt} = A\omega \cos{\omega t}##, whilst ##\frac{d^2s(t)}{dt^2} = -A\omega^2 \sin{\omega t}##.
 

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