Oscillation:Mass dropped on Vertical Spring

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Homework Statement



A woman bungee-jumper of mass 60 kg is attached to an elastic rope of natural length 15m. The rope behaves like a spring of spring constant k= 220Nm. The other end of the spring is attached to a high bridge. The woman jumps from the bridge.
a. Determine how far below the bridge she falls, before she instantaneously comes to rest.

Homework Equations



a= -(omega)Acos((omega)t)
omega^2=k/m
E=Ep+Ek
Ep=1/2mv^2
Ek=1/2 mv^2

The Attempt at a Solution


I'm not sure anymore, please help
 
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You can use conservation of energy but find the correct form of the potential energy. You have two forces, gravity and the elastic force of the cord, both of them contribute to the potential energy of the woman. ehild