Oscillation (particle movement)

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Homework Help Overview

The discussion revolves around a particle's motion in circular motion, specifically focusing on determining the x coordinate of the particle's velocity and acceleration at a given time. The problem is situated within the context of oscillations and rotational dynamics.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore different attempts to calculate the x coordinate of the particle's velocity and acceleration using provided equations. There are discussions about the correctness of the applied formulas and the interpretation of results. Some participants question whether the calculated velocity represents the total velocity or just the x component.

Discussion Status

There is acknowledgment of correct calculations for both parts of the problem, with some participants expressing uncertainty about their methods. Additionally, a participant seeks advice on study methods for upcoming physics topics, indicating a broader interest in learning strategies.

Contextual Notes

Participants mention concerns about accuracy in their calculations and the potential impact on their scores. There is also a reference to a separate forum for academic guidance, suggesting a desire for further exploration of study techniques.

Schulze
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Homework Statement


A particle rotates counterclockwise in a circle
of radius 4.4 m with a constant angular speed
of 11 rad/s. At t = 0, the particle has an x
coordinate of 2.9 m and y > 0 .
Part 1: Determine the x coordinate of the particle velocity
at t = 1.22 s.
Answer in units of m/s

Part 2: Determine the x coordinate of the particle acceleration
at t = 1.22 s.
Answer in units of m/s2


Homework Equations


x = Acos(wt + d)
where d was found in a previous part of the problem and confirmed correct by the program to be:
d = 0.8511870029
v = -wAsin(wt + d); vx = -wRsin(wt) = -vsin(wt)
a = -w2Acos(wt + d)

Note R and A are interchangeable

The Attempt at a Solution


Part 1:
Attempt 1: v = -wAsin(wt + d) = -(4.4 m)sin(11rad/s * 1.22s + 0.8511870029)
v = -4.360544081 m/s
Incorrect
Attempt 2: vx = -wRsin(wt)
vx = -(11rad/s)(4.4m)sin(11 rad/s * 1.22 s) ≈ -36.477666 m/s
vx = -vsin(wt) = (solution from Attempt 1)sin(wt)
vx = -(-4.360544081 m/s)sin(11 rad/s * 1.22 s) ≈ -3.286414681 m/s

Vastly different answers, don't know if incorrect because I don't want to get points deducted from score from trying random answers
 
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Schulze said:

Homework Statement


A particle rotates counterclockwise in a circle
of radius 4.4 m with a constant angular speed
of 11 rad/s. At t = 0, the particle has an x
coordinate of 2.9 m and y > 0 .
Part 1: Determine the x coordinate of the particle velocity
at t = 1.22 s.
Answer in units of m/s

Part 2: Determine the x coordinate of the particle acceleration
at t = 1.22 s.
Answer in units of m/s2


Homework Equations


x = Acos(wt + d)
where d was found in a previous part of the problem and confirmed correct by the program to be:
d = 0.8511870029
v = -wAsin(wt + d); vx = -wRsin(wt) = -vsin(wt)
a = -w2Acos(wt + d)

Note R and A are interchangeable

The Attempt at a Solution


Part 1:
Attempt 1: v = -wAsin(wt + d) = -(4.4 m)sin(11rad/s * 1.22s + 0.8511870029)
v = -4.360544081 m/s
Incorrect
Attempt 2: vx = -wRsin(wt)
vx = -(11rad/s)(4.4m)sin(11 rad/s * 1.22 s) ≈ -36.477666 m/s
vx = -vsin(wt) = (solution from Attempt 1)sin(wt)
vx = -(-4.360544081 m/s)sin(11 rad/s * 1.22 s) ≈ -3.286414681 m/s

Vastly different answers, don't know if incorrect because I don't want to get points deducted from score from trying random answers

Attempt 1: v = -wAsin(wt + d) = -(4.4 m)sin(11rad/s * 1.22s + 0.8511870029) is almost correct. You put A=4.4m into -wA. What happened to the w?
 
that's true. So if I multiply my result by 11 rad/s I get:
v = -47.96598498 m/s

However, is this total velocity in both x and y directions or is it the x coordinate of the velocity?

I would think that it would be the x coordinate, since we are taking the derivative of the position of the x coordinate?
 
Ok part 1 is correct!
 
Part 2: Determine the x coordinate of the particle acceleration
at t = 1.22 s.
Answer in units of m/s2


a = -w2Acos(wt + d)
a = -(11 rad/s)2(4.4 m)cos((11 rad/s * 1.22 s) + 0.8511870029)
a = 71.13887508 m/s2

which is correct!

Thank you.

But now I have more of a conceptual question that I would like to ask? Or rather, methodological?

I have a test coming up in 2 days over Dynamics of a Rigid Body, Statics and Elasticity, Oscillations, and Waves. (All in my Mechanics class)

Since it is my freshman year, taking mechanics, as a Physics major, I was wondering how it is that others study physics, or if you both could give me words or advice on how I should approach the study of physics.

Up until this point, I would read the textbook, work problems relevant to the readings, and if I was still confused I would Google the problem or concept.
I am not dissatisfied with this method, but I was just looking for someone else's perspective.
 
Schulze said:
Part 2: Determine the x coordinate of the particle acceleration
at t = 1.22 s.
Answer in units of m/s2a = -w2Acos(wt + d)
a = -(11 rad/s)2(4.4 m)cos((11 rad/s * 1.22 s) + 0.8511870029)
a = 71.13887508 m/s2

which is correct!

Thank you.

But now I have more of a conceptual question that I would like to ask? Or rather, methodological?

I have a test coming up in 2 days over Dynamics of a Rigid Body, Statics and Elasticity, Oscillations, and Waves. (All in my Mechanics class)

Since it is my freshman year, taking mechanics, as a Physics major, I was wondering how it is that others study physics, or if you both could give me words or advice on how I should approach the study of physics.

Up until this point, I would read the textbook, work problems relevant to the readings, and if I was still confused I would Google the problem or concept.
I am not dissatisfied with this method, but I was just looking for someone else's perspective.

Very welcome! What you are doing sounds fine to me, it worked for me. Except I didn't have google. But if you want more opinions on this there is a separate forum called Academic Guidance. You might want to post there. You'll probably get too many opinions, but there you go.
 
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