Why Is Answer A Correct for the Oscillation Problem?

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The discussion revolves around a physics question regarding oscillation, specifically why answer A is correct. The participant initially believed that since the ball was described as "stationary," all forces must be equal, leading them to choose answer C. However, upon further reflection, they realized that the forces must sum to zero, indicating that the vectors indeed add up correctly to support answer A. The confusion stemmed from the interpretation of the question and the nature of vector addition. Ultimately, the participant acknowledged their misunderstanding and clarified that the question pertains to IB Physics.
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Homework Statement


Hi! My question is about oscillation. The multiple choice answers and question is included in the picture attached! I also happen to know the answer is A by looking at the marscheme.


The Attempt at a Solution


I would've thought that since the ball is said to be held "stationary" in that position the forces would all have to be equal. Thus i would've thought C was the correct answer. If they had said that it's an oscillation where the ball is in position P and not mentioned it being held stationary, I would've answered A, however, knowing that the forces would've had to be unbalanced and acting towards the equilbrium point. Could anybody explain exactly why it's A? and not C? I think my problem is probably largely due to interpretation of the question. Thankyou for any replies!
 

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If the ball is stationary then the forces must sum to zero net force. If they were all equal, would the sum be zero? Remember, you're adding vectors here.
 
Hi, magiclink!
Is that IB Physics?
 
Hey! I just looked at the question and gave it a good look again. Turns out that the vectors did add vectorally to equal zero. A bit of an optical illusion to me. Thanks anyways! Sorry for wasting your time! :)


And yes, tis IB physics indeed. ;)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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