A 0.2 kg object, suspended from a spring with a spring constant of k = 10 N/m, is moving in simple harmonic motion and has an amplitude of 0.08 m. What is its velocity at the instant when its displacement is 0.04 m?
The Attempt at a Solution
i did v=root(9.8*.2/.2/.04) and this gave me 15.65, but the answer is 40 cm. how? please help; i do not understand this at all. also, can you please help on thsi question? i feel stupid.