Oscillations, velocity, elasticity

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SUMMARY

The discussion focuses on calculating the velocity of a 0.2 kg object in simple harmonic motion attached to a spring with a spring constant of k = 10 N/m and an amplitude of 0.08 m, at a displacement of 0.04 m. The correct approach involves using the position equation x = A*cos(w*t) and the angular frequency w = sqrt(k/m). The instantaneous velocity is derived from the velocity equation v = dx/dt = -A*w*sin(w*t), which requires determining the time corresponding to the displacement of 0.04 m.

PREREQUISITES
  • Understanding of simple harmonic motion principles
  • Knowledge of spring constants and mass-spring systems
  • Familiarity with trigonometric functions and their applications in physics
  • Ability to differentiate functions to find instantaneous rates of change
NEXT STEPS
  • Study the derivation of the position equation x = A*cos(w*t) in detail
  • Learn how to calculate angular frequency w = sqrt(k/m) for different spring-mass systems
  • Explore the concept of instantaneous velocity in the context of harmonic motion
  • Practice solving problems involving energy conservation in spring systems
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Students studying physics, particularly those focusing on mechanics and oscillatory motion, as well as educators seeking to clarify concepts related to simple harmonic motion and spring dynamics.

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Homework Statement


A 0.2 kg object, suspended from a spring with a spring constant of k = 10 N/m, is moving in simple harmonic motion and has an amplitude of 0.08 m. What is its velocity at the instant when its displacement is 0.04 m?


Homework Equations


v=root(F/m/l)



The Attempt at a Solution


i did v=root(9.8*.2/.2/.04) and this gave me 15.65, but the answer is 40 cm. how? please help; i do not understand this at all. also, can you please help on thsi question? i feel stupid.
https://www.physicsforums.com/showthread.php?p=3127238#post3127238
 
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For a vibrating spring-mass system the position equation is x=A*cos(w*t) where A=amplitude and w=angular frequency. w = sqrt(k/m). Plug x=.04 into equation to find time when displacement is .04 meters. velocity=dx/dt = -A*w*sin(w*t). Plug time into velocity equation to find instantaneous velocity.
 

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