Out of Phase Waves: Solving the Relevant Equation

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The discussion focuses on understanding the phase relationship between two waves, specifically that they are 90 degrees out of phase, or π/2. There is confusion regarding which wave is ahead; while it appears Y is ahead of X, the analysis shows that X oscillates upward before Y does. The key to resolving this is to examine the waveforms at the same time, particularly at t=0, to determine which wave is leading. The term "ahead" refers to the earlier position on the time axis, indicating that X is indeed ahead of Y by one quarter period. This clarification helps in accurately interpreting the phase difference between the two waves.
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2. Relevant equation

The Attempt at a Solution



I can see straight away that the waves are 90 degrees out of phase so pie/2.

But how is X ahead of Y? It looks like Y is ahead of X by pie/2.
 
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ravsterphysics said:
But how is X ahead of Y? It looks like Y is ahead of X by pie/2.
The horizontal axis is time, so X is oscillating up before Y is oscillating up. Look at the origin -- X is full size, and Y is just starting to move positive from zero... The key is to look at where the two waveforms are at the same time (say t=0) and ask yourself which one is "leading" the other. Makes sense?
 
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Another way to look at it..
"Ahead" means earlier in time. Earlier in the graph is to the left. The X curve is left of the Y curve by one quarter period.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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